Answer:
48%
Explanation:
Based on Gay-Lussac's law, the pressure is directly proportional to the temperature. To solve this question we must assume the temperature increases and all CO2 remains without reaction. The equation is:
P1T2 = P2T1
<em>Where Pis pressure and T absolute temperature of 1, initial state and 2, final state of the gas:</em>
P1 = 10.0atm
T2 = 1420K
P2 = ?
T1 = 730K
P2 = 10.0atm*1420K / 730K
P2 = 19.45 atm
The CO2 reacts as follows:
2CO2 → 2CO+ O2
Where 2 moles of gas react producing 3 moles of gas
Assuming the 100% of CO2 react, the pressure will be:
19.45atm * (3mol / 2mol) = 29.175atm
As the pressure rises just to 24.1atm the moles that react are:
24.1atm * (2mol / 19.45atm) = 2.48 moles of gas are present
The increase in moles is of 0.48 moles, a 100% express an increase of 1mol. The mole percent that descomposes is:
0.48mol / 1mol * 100 = 48%
Answer: 34.4 g
Explanation:
As 
is in excess, 
is the limiting reagent and thus it will limit the formation of products.
According to stoichiometry:
2 moles of hydrogen produce = 1 mole of 
2.5 moles of hydrogen produce = 
of
Mass of 
But as % yield is 86%, mass of produded is 
Thus 34.4 g of is produced.
Answer:
Student 3
Explanation:
This question lets us know something about how the density of a gas varies with temperature.
When a gas is heated, its molecules spread out and expand. When this happens, the volume of the gas increases. Remember that density is defined as mass/volume. Thus as the volume increases, the density of the gas decreases.
Therefore, the carbon dioxide rose up because the heat expanded the gas and it became less dense.
Answer:
E(Z) > E(X)
Explanation:
X => 4.2 x 10¹¹J/50 Nucleons = 8.4 x 10⁹ J/Nu
Z => 8.4 x 10¹¹J/80 Nucleons = 1.1 x 10¹⁰ J/Nu
E(Z)1.1 x 10¹¹J/Nu > E(X)8.4 x 10⁹J/Nu
Yes this is correct. Change the number of protons and you have a different element
