Which of the following is not a valid conversion factor?

Chemistry

1 answer:

Snezhnost [94]2 years ago

7 0

The last option, 1 meter/ 10 millimeters is not a valid conversion factor.

It should be 1000m Instead of 1 meter/ 10 millimeter since 1m=1000mm

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_____ bonds are formed when the electronegativity difference is 0.4 > 2.0. Give two examples:

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Ionic Bond is formed when the electronegativity difference is 0.4 > 2.0. Electronegativity is a term that can be defined as a tendency of an atom to attract electron towards its own self.

Explanation:

Electronegativity is a term that can be defined as a tendency of an atom to attract electron towards its own self.

An electronegativity of an atom is affected by

The atomic number of the atom
Secondly by the distance at which the valence electron are residing from the nucleus

1. In case the electronegativity difference (which is denoted by ΔEN) is less than 0.5 then the bond formed is known as Nonpolar covalent.

2. In case the ΔEN is in between 0.5 and 1.6, the bond formed is referred to as the Polar covalent

3. In case the ΔEN is more /greater than 2.0, then the bond formed is referred to as Ionic Bond

2 Examples of Ionic bonds

The formation of sodium fluoride, NaF, from a sodium atom and a fluorine atom is an example of Ionic bond formation.
Another example is the formation of NaCl from sodium (Na),which is a metal, and chloride (Cl), which is a nonmetal

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3 years ago

One way of obtaining pure sodium carbonate is through the decomposition of the mineral trona, Na3(CO3)(HCO3)·2H2O. 2Na3(CO3)(HCO

zhenek [66]

Percentage yield = (actual yield / theoretical yield) x 100%

The balanced equation for the decomposition is,
2Na₃(CO₃)(HCO₃)·2H₂O(s) → 3Na₂CO₃(s) + CO₂(g) + 5H₂O(g)

The stoichiometric ratio between Na₃(CO₃)(HCO₃)·2H₂O(s) and Na₂CO₃(s) is 2 : 3

The decomposed mass of Na₃(CO₃)(HCO₃)·2H₂O(s) = 1000 kg
= 1000 x 10³ g

Molar mass of Na₃(CO₃)(HCO₃)·2H₂O(s) = 226 g mol⁻¹
moles of Na₃(CO₃)(HCO₃)·2H₂O(s) = mass / molar mass
= 1000 x 10³ g / 226 g mol⁻¹
= 4424.78 mol

Hence, moles of Na₂CO₃ formed = 4424.78 mol x $\frac{3}{2}$
= 6637.17 mol

Molar mass of Na₂CO₃ = 106 g mol⁻¹

Hence, mass of Na₂CO₃ = 6637.17 mol x 106 g mol⁻¹
= 703540.02 g
= 703.540 kg

Hence, the theoretical yield of Na₂CO₃ = 703.540 kg
Actual yield of Na₂CO₃ = 650 kg

Percentage yield = (650 kg / 703.540 kg) x 100%
= 92.34%

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3 years ago

What is the pH of a 1.7 × 10⁻⁴ M HClO₄ solution?

Mamont248 [21]

Ph= -log[h30]

Ph= -log[1.7x10^-4]

pH= 3.77

pH is acidic

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3 years ago

Which term is used to measure a star's brightness?

Romashka-Z-Leto [24]

Answer:

Magnitude

Explanation:

Astronomers define star brightness in terms of magnitude (how bright the star appears from Earth)

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3 years ago

The Supreme Court case of Marbury v. Madison

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The Supreme Court case of Marbury v. Madison (1803) strengthened the power of the judicial branch by "(4) granting federal courts the power to declare
laws unconstitutional"

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4 years ago