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Kaylis [27]
4 years ago
6

Use a graph to solve the equation on the interval

Mathematics
1 answer:
artcher [175]4 years ago
3 0
sec(x)=-\sqrt{2}\qquad 
\begin{cases}
sec(\theta)=\cfrac{1}{cos(\theta)}
\end{cases}
\\ \quad \\
\cfrac{1}{cos(x)}=-\sqrt{2}\implies \cfrac{1}{-\sqrt{2}}=cos(x)
\\ \quad \\
cos^{-1}\left( \cfrac{1}{-\sqrt{2}} \right)=cos^{-1}[cos(x)]
\\ \quad \\
cos^{-1}\left(- \cfrac{1}{\sqrt{2}} \right)=x
\\ \quad \\
\textit{now, check your Unit Circle for those }\measuredangle x
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Nastasia [14]

Step-by-step explanation:

given :

2x - 3y = 11

-6x + 8y = 34

find : the solutions of the system by using Cramers Rule.

solutions:

in the matrix 2x2 form =>

[ 2 -3] [x] [11]

=

[-6 8] [ y] [34]

D =

| 2 -3 |

|-6 8 |

= 8×2 - (-3) (-6)

= 16-18 = -2

Dx = | 11 -3 |

| 34 8 |

= 11×8 - (-3) (34)

= 88 + 102

= 190

Dy = | 2 11 |

|-6 34 |

= 2×34 - (-6) (11)

= 68 + 66

= 134

x = Dx/D = 190/-2 = -95

y = Dy/D = 134/-2 = -67

the solutions = {-95, -67}

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Step-by-step explanation:

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3 years ago
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Y=1 I hope this helps :)
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Is 10x-7 equivalent to (7x-5)-(3x-2)​
ValentinkaMS [17]

no, because (7x-5) - (3x-2) = 4x-3

This would, however, be true if the equation was (7x-5) + (3x-2), but since the equation is subtracting instead of adding the equation isn't equivalent to 10x-7.

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