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Kaylis [27]
3 years ago
6

Use a graph to solve the equation on the interval

Mathematics
1 answer:
artcher [175]3 years ago
3 0
sec(x)=-\sqrt{2}\qquad 
\begin{cases}
sec(\theta)=\cfrac{1}{cos(\theta)}
\end{cases}
\\ \quad \\
\cfrac{1}{cos(x)}=-\sqrt{2}\implies \cfrac{1}{-\sqrt{2}}=cos(x)
\\ \quad \\
cos^{-1}\left( \cfrac{1}{-\sqrt{2}} \right)=cos^{-1}[cos(x)]
\\ \quad \\
cos^{-1}\left(- \cfrac{1}{\sqrt{2}} \right)=x
\\ \quad \\
\textit{now, check your Unit Circle for those }\measuredangle x
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Respuesta:

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Explicación paso a paso:

El volumen de un prisma rectangular se calcula usando la relación:

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Por eso,

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De la pregunta, no se da el volumen, por lo tanto, tomamos el volumen como V en otro para calcular la altura, h

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