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3 years ago

Use a graph to solve the equation on the interval

1 answer:

3 0

$sec(x)=-\sqrt{2}\qquad 
\begin{cases}
sec(\theta)=\cfrac{1}{cos(\theta)}
\end{cases}
\\ \quad \\
\cfrac{1}{cos(x)}=-\sqrt{2}\implies \cfrac{1}{-\sqrt{2}}=cos(x)
\\ \quad \\
cos^{-1}\left( \cfrac{1}{-\sqrt{2}} \right)=cos^{-1}[cos(x)]
\\ \quad \\
cos^{-1}\left(- \cfrac{1}{\sqrt{2}} \right)=x
\\ \quad \\
\textit{now, check your Unit Circle for those }\measuredangle x$

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Someone help me asap pleaseee!!

gogolik [260]

Answer:

B is correct.

6 0

2 years ago

A florist arranges 4 flower arrangements in 92 minutes.

Black_prince [1.1K]

Answer:

$\boxed {\boxed {\sf 9 \ arrangements }}$

Step-by-step explanation:

Let's set up a proportion using the following setup:

$\frac{arrangements}{minutes} =\frac{arrangements}{minutes}$

We know that the florist can arrange 4 in 92 minutes.

$\frac{4 \ arrangements}{92 \ minutes} = \frac{arrangements}{minutes}$

We don't know how many the florist can arrange in 207 minutes, so we say x arrangements can be completed in 207 minutes.

$\frac{4 \ arrangements}{92 \ minutes} = \frac{ x \ arrangements}{ 207 \ minutes}$

$\frac{4}{92} =\frac{x}{207}$

Solve for x by isolating it on one side of the proportion.

x is being divided by 207. The inverse of division is multiplication. Multiply both sides of the proportion by 207.

$207*\frac{4}{92}=\frac{x}{207}*207$

$207*\frac{4}{92}=x$

$207*0.0434782609=x$

$9=x$

The florist can arrange <u>9 arrangements</u> in 207 minutes.

5 0

3 years ago

Need help please and thanks

madreJ [45]

Answer:

2. n = 11

4. g = -2

6. t = 21

8. n = 4

10. y = -1

Step-by-step explanation:

2. 63 = -3(1 - 2n)

Dividing both the side by negative 3 we get

$-21=1-2n\\2n=1+21\\2n=22\\n=\frac{22}{2} \\\therefore n=11$

4. -g + 2(3 + g) = -4(g + 1)

First we will open the bracket by distributive property A( B +C) = AB + AC

$-g+2\times 3 + 2\times g = -4\times g + -4\times 1\\-g+6+ 2g=-4g-4\\\textrm{we will take all the g term the left side and the constant to the right side}\\4g-g+2g=-6-4\\5g=-10\\g=\frac{-10}{5}\\\therefore g=-2$

6.-3(t +5 ) + (4t + 2) = 8

Using distributive property A( B +C) = AB + AC we get

$-3\times t + -3\times 5 + 4t + 2=8\\-3t-15+ 4t + 2=8\\t=8+15-2\\t=21\\\therefore t=21\\$

8. -8 - n = -3(2n -4)

Using distributive property A( B +C) = AB + AC we get

$-8 - n = -3\times 2n - -3\times4\\-8-n=-6n+12\\\textrm{all the n terms to the left inside and the constant of the right-hand side}\\6n-n=8+12\\5n=20\\n=\frac{20}{5}\\ \therefore n= 4$

10. -4( 2 - y) + 3y = 3(y - 4)

Using distributive property A( B +C) = AB + AC we get

$-4\times 2 --4\times y + 3y = 3\times y -3\times 4\\-8+4y+3y =3y-12\\\textrm{all the y terms to the left side and the constant to the right side}\\4y+3y-3y=-12+8\\4y=-4\\y=\frac{-4}{4}\\ \therefore y=-1$