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laila [671]
3 years ago
5

A recipe calls for 1.2 cups of oil. How many liters of oil is this?

Chemistry
2 answers:
horsena [70]3 years ago
5 0

Here you need to know how many litters are a measuring cup.

1 cup = 250ml = 0.25 liters.

Now, do the cross multiplication:

1 cup ----- 0.25 liters.

1.2 cups --X= 1.2 (cups * 0.25 liters)/ 1 cup = 0.3 liters

So, 1.2 cups of oil represent 0.3 liters or 300ml.

Nadusha1986 [10]3 years ago
3 0
.3 liters... im pretty sure this is correct!!
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A system fitted with a piston expands when it absorbs 53.1 ) of heat from the surroundings. The piston is working against a pres
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Answer:

d. 60.8 L

Explanation:

Step 1: Given data

  • Heat absorbed (Q): 53.1 J
  • External pressure (P): 0.677 atm
  • Final volume (V2): 63.2 L
  • Change in the internal energy (ΔU): -108.3 J

Step 2: Calculate the work (W) done by the system

We will use the following expression.

ΔU = Q + W

W = ΔU - Q

W = -108.3 J - 53.1 J = -161.4 J

Step 3: Convert W to atm.L

We will use the conversion factor 1 atm.L = 101.325 J.

-161.4 J ×  1 atm.L/101.325 J = -1.593 atm.L

Step 4: Calculate the initial volume

First, we will use the following expression.

W = - P × ΔV

ΔV = - W / P

ΔV = - 1.593 atm.L / 0.677 atm = 2.35 L

The initial volume is:

V2 = V1 + ΔV

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7 0
3 years ago
Write the balanced equation for the reaction of aqueous Pb ( ClO 3 ) 2 with aqueous NaI . Include phases. chemical equation: Wha
Citrus2011 [14]

<u>Answer:</u> The mass of lead iodide produced is 9.22 grams

<u>Explanation:</u>

To calculate the molarity of solution, we use the equation:

\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}

Molarity of NaI = 0.200 M

Volume of solution = 0.200 L

Putting values in above equation, we get:

0.200M=\frac{\text{Moles of NaI}}{0.200}\\\\\text{Moles of NaI}=(0.200mol/L\times 0.200L)=0.04moles

The chemical equation for the reaction of NaI and lead chlorate follows:

Pb(ClO_3)_2(aq.)+2NaI(aq.)\rightarrow PbI_2(s)+2NaClO_3(aq.)

By Stoichiometry of the reaction:

2 moles of NaI reacts produces 1 mole of lead iodide

So, 0.04 moles of NaI will react with = \frac{1}{2}\times 0.04=0.02mol of lead iodide

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

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Putting values in above equation, we get:

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6 0
3 years ago
How many atoms are in 165 g of calcium?
Whitepunk [10]
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hope this helps!
4 0
3 years ago
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