There are 4 lone pairs of electrons present in the carbon dioxide molecule
Answer:

In which [Ag+] in negligibly small and the concentration of each reactant is 1.0 M
The answer is A) PO43- < NO3- < Na+
Explanation:
Ag+ is removed from the solution just like PO43-, so there are just 2 possible answers at this point: a or b. Then we can notice that Na3PO4 releases 3 moles of Na+ and just 1 mole of NO3-
We have 100mL of each reactant with the same concentration for both (1.0 M) so:
(0.1)(1)(3)= 0.3 mol Na+
(0.1)(1)= 0.1 mol NO3-
so PO43- < NO3- < Na+
Answer:
The value of the equilibrium constant = 5.213
Explanation:
Here
(equilibrium constant) is referred to as the partial pressure of product divided by the partial pressure of reactant with each pressure term raised to power that is equal to its stoichiometric coefficient in balanced equation
.
As such only gas appear in
expression as solids takes a value of 1;
SO ; in the given equation from the question:
2 A (g) + B (s) ----> 2 C(s) + D (g)
![K_p = \dfrac{[D]}{[A]^2}](https://tex.z-dn.net/?f=K_p%20%3D%20%5Cdfrac%7B%5BD%5D%7D%7B%5BA%5D%5E2%7D)


The value of the equilibrium constant = 5.213