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3 years ago

What is the values of x and y

Mathematics

2 answers:

Vladimir [108]3 years ago

8 0

Answer:

Hey there!

I can't see the full problem, but if when x=0.5, y=4, then when x=4, y=32, and when x=9, y=72. You multiply by a common multiple to get from x to y.

Hope this helps :)

Korvikt [17]3 years ago

6 0

Answer:

If you have given an equation, you see the x and y in it. Just taking second equation and think any common factor between x's variable. With common factor, multiply both and you will find the value of y and put it in any equation, you will find the value of X.

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Hannah claims that people who live in southern states spend 9 hours more per week outside than do people in northern states. She

Aneli [31]

Answer: Hello your question is incomplete below is the missing part

Which of the following statements about Hannah’s claim is supported by the interval?

A) Hannah is likely to be incorrect because the difference in the sample means was 18.6−14.4=4.218.6−14.4=4.2 hours.

B) Hannah is likely to be incorrect because 9 is not contained in the interval.

C)The probability that Hannah is correct is 0.99 because 9 is not contained in the interval.

D)The probability that Hannah is correct is 0.01 because 9 is not contained in the interval.

E)Hannah is likely to be correct because the difference in the sample means (18.6−14.4=4.2)(18.6−14.4=4.2) is contained in the interval.

Answer : Hannah is likely to be incorrect because 9 is not contained in the interval. ( B )

Step-by-step explanation:

The statement that is supported by the interval in Hannah's claim is that

Hannah is likely to be incorrect because 9 is not contained in the interval.

5 0

3 years ago

Select ALL the correct answers.

IgorC [24]

Answer:

A. 4(x - 4) + 2(3x² + 3x - 20)

C. (11x² + 7x - 55)-(5x² - 3x + 1)

F. (3x² + 5x - 28) + (3x² + 5x - 28)

Step-by-step explanation:

Given:

(3x-7)(2x+8)

= 6x² + 24x - 14x - 56

=6x² + 10x - 56

A. 4(x - 4) + 2(3x² + 3x - 20)

= 4x - 16 + 6x² + 6x - 40

= 6x² + 10x - 56

B. (3x² + 5x - 28) - (2x² + 4x + 28)

= 3x² + 5x - 28 - 2x² - 4x - 28

= x² + x - 56

C. (11x² + 7x - 55)-(5x² - 3x + 1)

= 11x² + 7x - 55 - 5x² + 3x - 1

= 6x² + 10x - 56

D. 4(x - 4) - 2(3x² + 3x - 20)

= 4x - 16 - 6x² - 6x + 40

= - 6x² - 2x + 24

E. (11x² + 7x - 55)-(5x² - 3x + 2)

= 11x² + 7x - 55 - 5x² + 3x - 2

= 11x² - 5x² + 7x + 3x - 55 - 2

= 6x² + 10x - 57

F. (3x² + 5x - 28) + (3x² + 5x - 28)

= 3x² + 5x - 28 + 3x² + 5x - 28

= 6x² + 10x - 56

7 0

2 years ago

Create a polynomial function in standard form with a leading coefficient of 2 and zeros at 0 1 and 3 brainly

TEA [102]

Answer:

$P(x) = 2x^3 - 8x^2 + 6x$

Step-by-step explanation:

Given

$p =2$ -- Leading coefficient

$Zeros: 0, 1\ and\ 3$

Required

Determine the polynomial

Represent the zeros with a, b and c.

Such that

$a = 0$

$b = 1$

$c = 3$

The polynomial is:

$P(x) = p * (x - a) * (x - b) * (x - c)$

$P(x) = 2 * (x - 0) * (x - 1) * (x - 3)$

$P(x) = 2x * (x - 1) * (x - 3)$

Open bracket

$P(x) = (2x^2 - 2x) * (x - 3)$

$P(x) = 2x^3 - 6x^2 - 2x^2 + 6x$

$P(x) = 2x^3 - 8x^2 + 6x$

5 0

3 years ago

How does the graph of g(x) = −(x + 3)^4 compare to the parent function of f(x) = x^4

kotykmax [81]

Answer: Option D

g(x) is shifted 3 units to the left and reflected over the x-axis.

Step-by-step explanation:

If we have a main function $f (x) = x ^ 4$

And we perform the transformation:

$g (x) = f (x + h) = (x + h) ^ 4$

Then it is fulfilled that:

If $h> 0$ the graph of f(x) moves horizontally h units to the left

If $h$ the graph of f(x) moves horizontally h units to the right

If we have a main function $f (x) = x ^ 4$

And we perform the transformation:

$g (x) = -f(x) = -x ^ 4$

Then it is fulfilled that:

The graph of g(x) is equal to the graph of f(x) reflected on the x axis

In this case we have to:

$g(x) = -(x + 3)^4$ and $f(x) = x^4$

Therefore $h=3>0$ and $g(x) = -f(x)$

This mean that: g(x) is shifted 3 units to the left and reflected over the x-axis.

6 0

3 years ago

Please Help - Suppose f(t)=6t−8−−−−√.

Gnoma [55]

$(a)\\\\\\\text{Given that,}~~\\\\ f(t) =\dfrac 6{\sqrt{t-8}}\\\\\\\\\implies f'(t) = 6\left[\dfrac{\left(\sqrt{t-8}\right) \cdot 0 - \dfrac 1{2\sqrt{t-8 }}}{\left(\sqrt{t-8}\right)^2}\right]\\\\\\\\\implies f'(t) = -6\left(\dfrac {\dfrac 1{2\sqrt{t-8}}}{t-8}\right)\\\\\\\implies f'(t) = -6\left(\dfrac{1}{2\sqrt{t-8} (t-8)}\right)\\\\\\\implies f'(t) =-\dfrac 3{(t-8)^{\tfrac 32}}$

(b)

$\text{Given that,}\\\\y=f(t)\\\\\text{Slope of y,} ~~ f'(t) =-\dfrac 3{(t-8)^{\tfrac 32}}\\\\\text{At point (33, 6/5)}\\\\\\f'(t) = -\dfrac 3{(33-8)^{\tfrac 32}} = - \dfrac 3{ (25)^{ \tfrac 32}} = - \dfrac 3{5^3} = -\dfrac 3{125}\\\\\\\text{Equation with given points,}\\\\y - \dfrac 65 = -\dfrac 3{125} ( t - 33)\\\\\\\implies y =-\dfrac 3{125} t +\dfrac{99}{125} + \dfrac 65\\\\\\\implies y = -\dfrac 3{125} t +\dfrac{249}{125}$

8 0

2 years ago