Answer:
Explanation:
The condition for translation equilibrium is that is that the net force acting on the body must be zero.
The sum all the external forces acting on the body in horizontal as well as vertical direction must be zero.
∑Fₓ=0 and ∑Fy=0
now if the above two condition are satisfied the rigid body is said to be in translational equilibrium.
God bless... hope this help to clear your doubt.
Answer:
The magnitude of the change in momentum of the stone is 5.51kg*m/s.
Explanation:
the final kinetic energy = 1/2(0.15)v^2
1/2(0.15)v^2 = 70%*1/2(0.15)(20)^2
v^2 = 21/0.075
v^2 = 280
v = 16.73 m.s
if u is the initial speed and v is the final speed, then:
u = 20 m/s and v = - 16.73m/s
change in momentum = m(v-u)
= 0.15(- 16.73-20)
= -5.51 kg*m.s
Therefore, The magnitude of the change in momentum of the stone is 5.51kg*m/s.
