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2 years ago

Which substance have the same number of carbon (C) atoms?

Chemistry

2 answers:

Vladimir79 [104]2 years ago

7 0

Answer:

Carbon monoxide

Explanation:

Carbon dioxide and carbon monoxide have the same number of carbon atoms.

Mark Brainliest

creativ13 [48]2 years ago

6 0

Carbon monoxide would be your answer.

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How many grams of al2o3 (mm = 101. 96 g/mol) are produced when 91. 7 grams o2 reacts with excess aluminum?

Ronch [10]

Answer:

Explanation:

1. Write down the balanced equation

2. Use molar mass of O2 (32g/mol) divided by the given mass to derive the amount of mols

3. multiply the answer by 2/3 (divide by 3 then multiply by 2), to ensure the mols are in correct proportion

4. Use given molar mass and multiply it by the amount

5. Make sure to use proper significant digits (3 in this case) and units :)

7 0

2 years ago

2. What mass of sodium chloride is produced when chlorine gas reacts with 2.29 grams of sodium iodide? The unbalanced equation i

Damm [24]

Answer:

0.88g

Explanation:

The reaction equation:

2NaI + Cl₂ → 2NaCl + I₂

Given parameters:

Mass of Sodium iodide = 2.29g

Unknown:

Mass of NaCl = ?

Solution:

To solve this problem, we work from the known to the unknown.

First find the number of NaI from the mass given;

Number of moles = $\frac{mass}{molar mass}$

Molar mass of NaI = 23 + 126.9 = 149.9g/mol

Now insert the parameters and solve;

Number of moles = $\frac{2.29}{149.9}$ = 0.015mol

So;

From the balanced reaction equation;

2 moles of NaI produced 2 moles of NaCl

0.015mole of NaI will produce 0.015mole of NaCl

Therefore;

Mass = number of moles x molar mass

Molar mass of NaCl = 23 + 35.5 = 58.5g/mol

Now;

Mass of NaCl = 0.015 x 58.5 = 0.88g

8 0

3 years ago

Vitamins are food. True OR False

Serga [27]

Answer: Hello!

False

Explanation:

hope you do good!they are in ur food though

6 0

3 years ago

Read 2 more answers

PLEASE HELPPP!!!!

aksik [14]

Answer:

b. 11.90 Liters

Explanation:

The balanced equation for the mentioned reaction is:

3O₂ + 4Al → 2Al₂O₃,

It is clear that 3.0 moles of O₂ react with 4.0 moles of Al to produce 2.0 Al₂O₃.

Firstly, we need to calculate the no. of moles (n) of 36.12 g of Al₂O₃:

n = mass/molar mass = (44.18 g)/(101.96 g/mol) = 0.4333 mol.

using cross multiplication:

3.0 mol of O₂ produces → 2.0 mol of Al₂O₃.

??? mol of O₂ produces → 0.4333 mol of Al₂O₃.

∴ The no. of moles of O₂ needed to produce 36.12 grams of Al₂O₃ = (3.0 mol)(0.4333 mol)/(2.0 mol) = 0.65 mol.

Now, we can find the volume of O₂ used during the experiment:

We can use the general law of ideal gas: PV = nRT.

where, P is the pressure of the gas in atm (P = 1.3 atm).

V is the volume of the gas in L (V = ??? L).

n is the no. of moles of the gas in mol (n = 0.65 mol).

R is the general gas constant (R = 0.0821 L.atm/mol.K),

T is the temperature of the gas in K (T = 290 K).

∴ V = nRT/P = (0.65 mol)(0.0821 L.atm/mol.K)(290 K)/(1.3 atm) = 11.9 L.

So, the right choice is: b. 11.90 Liters.

8 0

3 years ago

Lead metal can be extracted from a mineral called galena, which contains 86.6% lead by mass. a particular ore contains 68.5% gal

rjkz [21]

The volume of sphere can be calculated using the following formula:

$V=\frac{4}{3}\pi r^{3}$

Here, r is radius of the sphere which is 8 cm. Putting the value,

$V=\frac{4}{3}\pi r^{3}=\frac{4}{3}(3.14)(8 cm)^{3}=2143.57 cm^{3}$

This is equal to the volume of lead, density of lead is $11.34 g/cm^{3}$ thus, mass of lead can be calculated as follows:

$m=d\times V=11.34 g/cm^{3}\times 2143.57 cm^{3}=2.43\times 10^{4}g$

Let the mass of ore be 1 g, 68.5% of galena is obtained by mass, thus, mass of galena obtained will be 0.685 g.

Now, 86.6% of lead is obtained from this gram of galena, thus, mass of lead will be:

m=0.685×0.866=0.5932 g

Therefore, 0.5932 g of lead is obtained from 1 g of ore, if the efficiency is 100%.

For 92.5% efficiency, mass of lead obtained will be:

$m=\frac{92.5}{100}\times 0.5932=0.5487 g$

Thus, 1 g of lead obtain from $\frac{1}{0.5487}=1.822$ grams of ore.

Thus, $2.43\times 10^{4} g$ of lead obtain from:

$2.43\times 10^{4}\times 1.822=4.42\times 10^{4}g=44.2 kg$

Therefore, mass of ore required to make lead sphere is 44.2 kg.

4 0

3 years ago

Read 2 more answers