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Mars2501 [29]
3 years ago
13

You want to test how the mass of a reactant affect the speed of a reaction which of the following is an example of a controlled

experiment to test this
Chemistry
1 answer:
emmainna [20.7K]3 years ago
6 0

Answer:A

Explanation:

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Match the following vocabulary words with the correct definitions.
son4ous [18]

Answer:

1 mass

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4 0
2 years ago
The molar absorptivity for aqueous solutions of phenol at 211 nm is 6.17x103L/mol/cm. Calculate the linear range of phenol conce
Scilla [17]

Explanation:

The given data is as follows.

          \lambda = 211 nm,          \sum = 6.17 \times 10^{3} mol/L/cm

           l = 1 cm,             7% < Transmittance < 85%

Suppose the aqueous solution follows Lambert-Beer's law. Therefore,

                   Absorbance = -log \frac{\text{Percentage transmittance}}{100}

Hence, for 7% transmittance the value of absorbance will be as follows.

                  Absorbance = -log \frac{7}{100}

                           A_{1} = 1.155

For 85% transmittance the value of absorbance will be as follows.

                 Absorbance = -log \frac{85}{100}

                           A_{2} = 0.07058

According to Lambert-Beer's law.

                  A = \sum \times l \times C

where,       A = absorbance

                 \sum = molar extinction coefficient

                 C = concentration

Therefore, concentration for 7% absorbance is as follows.

                    A_{1} = \sum \times l \times C_{1}

                  C_{1} = \frac{1.155}{6.17 \times 10^{3} \times 1}

                                  = 0.187 \times 10^{-3} mol/L

                                  = 0.187 mmol/L

Concentration for 85% absorbance is as follows.

                   A_{2} = \sum \times l \times C_{2}

                  C_{2} = \frac{0.07058}{6.17 \times 10^{3} \times 1}

                                  = 0.01144 \times 10^{-3} mol/L

                                  = 0.01144 mmol/L

Thus, we can conclude that linear range of phenol concentration is 0.01144 mmol/L to 0.187 mmol/L.

6 0
3 years ago
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Anettt [7]

Answer:battery in a flashlight so A

Explanation:

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A sample of helium gas has a volume of 620. Ml at a temp of 500 K. If we decrease the temperature to 100K while keeping the pres
Ne4ueva [31]

Answer:

A sample of helium gas has a volume of 620mL at a temperature of 500 K. If we ... to 100 K while keeping the pressure constant, what will the new volume be?

Explanation:

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