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antoniya [11.8K]
3 years ago
14

4 g of ag2so4 will dissolve in 1l of water. calculate the solubility product (ksp) for silver (i) sulfate.

Chemistry
1 answer:
Bas_tet [7]3 years ago
7 0
Reaction of dissociation: Ag₂SO₄ → 2Ag⁺ + SO₄²⁻.
m(Ag₂SO₄) = 4 g.
V(Ag₂SO₄) = 1 l.
n(Ag₂SO₄) = m(Ag₂SO₄) ÷ M(Ag₂SO₄).
n(Ag₂SO₄) = 4 g ÷ 311,8 g/mol.
n(Ag₂SO₄) = 0,0128 mol.
n(Ag⁺) = 2 · 0,0128 mol = 0,0256 mol.
n(Ag₂SO₄) = n(SO₄²⁻) = 0,0128 mol.
c(Ag⁺) = n ÷ V = 0,0256 mol ÷ 1 l = 0,0256 mol/l.
Ksp = c(Ag⁺)² · c(SO₄²⁻).
Ksp = (0,0256 mol/l)² · 0,0128 mol/l.
Ksp = 8,3·10⁻⁶.

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puteri [66]

Answer:

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The dissociation of ammonium sulphide, (NH₄)₂S when dissolved in water is given in the equation below:

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How many atoms are there in 2.43 g of calcium?
Evgen [1.6K]

Answer:

Explanation:

We're asked to calculate the number of atoms of

Ca

in

153

g Ca

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What we must first do is convert the given mass of calcium to moles of calcium, using its molar mass (referring to a periodic table, this is

40.08

g

mol

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153

g Ca

(

1

mol Ca

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=

3.82

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Using Avogadro's number,

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×

10

23

atoms Ca

1

mol Ca

)

=

2.30

×

10

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atoms Ca

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