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Natali [406]
4 years ago
14

Rylan is hiking in Death valley. He starts at an elevation of 250 feet above sea level and hikes to an 2300 above sea level. How

much did his altitude change?​
Mathematics
1 answer:
aalyn [17]4 years ago
8 0

Answer:

250+2300=2350

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Can someone plz help with 5, 6 and 7
juin [17]

Answer:

750 people will come in at 15 hours.

Step-by-step explanation:

350 divided by 7=50       50 times 15=750

sorry i don't know  the rest

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3 years ago
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the area of a gymnasium floor is 264 square yard. the floor is 11 yards wide . how long is the floor?
Alekssandra [29.7K]
Area = Length x Width (A = L x W)

A = 264, W = 11, L = ?

Rewrite the equation to find L. In order to reverse multiplication, you must divide.

L = A / W

L = 264 / 11 = 24 yards
4 0
3 years ago
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What is 4(-8x+5)=-32x26
Ksivusya [100]

Answer:

x = -25.375

Step-by-step explanation:

4(-8x+5) = -32 x 26

-32x + 20 = 832

-32 = 812

x = -25.375

6 0
3 years ago
The resistance of a wire varies directly with its length and inversely with the square of its diameter. If 100 feet of wire with
DaniilM [7]

Answer:

  14 ohms

Step-by-step explanation:

The resistance varies directly with length, so increasing the length by a factor will increase the resistance by the same factor.

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The length of the wire increased by a factor of 1.4 from 100 ft to 140 ft. That means the resistance will increase by a factor of 1.4 from 10 ohms to 14 ohms. (The diameter did not change.)

The longer wire will have a resistance of 14 ohms.

4 0
2 years ago
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y = c1 cos(5x) + c2 sin(5x) is a two-parameter family of solutions of the second-order DE y'' + 25y = 0. If possible, find a sol
TEA [102]

Answer:

y = 2cos5x-9/5sin5x

Step-by-step explanation:

Given the solution to the differential equation y'' + 25y = 0 to be

y = c1 cos(5x) + c2 sin(5x). In order to find the solution to the differential equation given the boundary conditions y(0) = 1, y'(π) = 9, we need to first get the constant c1 and c2 and substitute the values back into the original solution.

According to the boundary condition y(0) = 2, it means when x = 0, y = 2

On substituting;

2 = c1cos(5(0)) + c2sin(5(0))

2 = c1cos0+c2sin0

2 = c1 + 0

c1 = 2

Substituting the other boundary condition y'(π) = 9, to do that we need to first get the first differential of y(x) i.e y'(x). Given

y(x) = c1cos5x + c2sin5x

y'(x) = -5c1sin5x + 5c2cos5x

If y'(π) = 9, this means when x = π, y'(x) = 9

On substituting;

9 = -5c1sin5π + 5c2cos5π

9 = -5c1(0) + 5c2(-1)

9 = 0-5c2

-5c2 = 9

c2 = -9/5

Substituting c1 = 2 and c2 = -9/5 into the solution to the general differential equation

y = c1 cos(5x) + c2 sin(5x) will give

y = 2cos5x-9/5sin5x

The final expression gives the required solution to the differential equation.

3 0
3 years ago
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