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slavikrds [6]
3 years ago
14

PLEASE FAST ANSWER THIS AND DONT MIND MY WORK PLEASE!!!

Mathematics
1 answer:
Amiraneli [1.4K]3 years ago
7 0
66 for the first and 36 for the other one
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When truckers are on long-haul drives, their driving logs must reflect their average speed. Average speed is the total distance
bekas [8.4K]

a) v=\frac{d_{tot}}{t_{tot}}=\frac{(3 h)(60 mph)+20 mi}{3 h +t_2}

The average speed is equal to the ratio between the total distance (d_{tot} and the total time taken (t_{tot}):

v=\frac{d_{tot}}{t_{tot}}

the distance travelled by the trucker in the first 3 hour can be written as the time multiplied by the velocity:

d_1 = (3 h)(60 mph)=180 mi

So the total distance is

d_{tot}=d_1 +d_2 = 180 mi+20 mi=200 mi

The total time is equal to the first 3 hours + the time taken to cover the following 20 miles in the city:

t_{tot}=3 h +t_2

So, the equation can be rewritten as:

v=\frac{d_{tot}}{t_{tot}}=\frac{(3 h)(60 mph)+20 mi}{3 h +t_2}


b) 0.50 h (half a hour)

Since we know the value of the average speed, v=57.14 mph, we can substitute it into the previous equation to find the value of t_2, the time the trucker drove in the city:

v=\frac{200 mi}{3h +t_2}\\3h+t_2 = \frac{200 mi}{v}\\t_2 = \frac{200 mi}{v}-3h=\frac{200 mi}{57.14 mph}-3 h=0.50 h


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Step-by-step explanation:

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(5x)^2 + x^2 = c^2

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25 points please help thanks
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Answer:

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(-2, -5)

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2 years ago
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