Ba²⁺ + 2Cl⁻ + 2H⁺ + SO₄²⁻ = BaSO₄ (precipitate) + 2H⁺ + 2Cl⁻
Ba²⁺ + SO₄²⁻ = BaSO₄
Given :
Mass of oxygen containing carbon monoxide (CO) is 2.666 gram .
To Find :
How many grams of carbon (C) would be present in carbon monoxide (CO) that contains 2.666 grams of oxygen (O) .
Solution :
By law of constant composition , a given chemical compound always contains its component elements in fixed ratio (by mass) and does not depend on its source and method of preparation.
So , volume of solution does not matter .
Moles of oxygen ,
.
Now , molecule of CO contains 1 mole of C .
So , moles of C is also 0.167 mole .
Mass of carbon ,
.
Therefore , mass of carbon is 2 grams .
Hence , this is the required solution .
The new pressure inside the syringe will be 1.25 atm
<h3>Gas law</h3>
At constant temperatures, the volume of a gas is inversely proportional to its pressure.
Thus: P1V1 = P2V2
In this case, P1 = 3.0 atm, V1 = 89.6 mL, V2 = 215 mL
P2 = P1V1/V2
= 3 x 89.6/215
= 1.25 atm
More on gas laws can be found here: brainly.com/question/1190311
Acid A, assuming the two acids have the same pH. The M stands for molarity which is how concentrated a substance is (basically the higher the molarity the more concentrated the acid is). However, pH refers to how acidic a substance is. If the two acids have different levels of acidity, the answer may be different.
Answer: B. Allow light to pass through. :)