A certain water tower hold 4.6×10^5 gallons of water. find the volume of that water in liters.
2 answers:
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Answer:
See explanation below
Explanation:
The question is incomplete, cause you are not providing the structure. However, I found the question and it's attached in picture 1.
Now, according to this reaction and the product given, we can see that we have sustitution reaction. In the absence of sodium methoxide, the reaction it's no longer in basic medium, so the sustitution reaction that it's promoted here it's not an Sn2 reaction as part a), but instead a Sn1 reaction, and in this we can have the presence of carbocation. What happen here then?, well, the bromine leaves the molecule leaving a secondary carbocation there, but the neighbour carbon (The one in the cycle) has a more stable carbocation, so one atom of hydrogen from that carbon migrates to the carbon with the carbocation to stabilize that carbon, and the result is a tertiary carbocation. When this happens, the methanol can easily go there and form the product.
For question 6a, as it was stated before, the mechanism in that reaction is a Sn2, however, we can have conditions for an E2 reaction and form an alkene. This can be done, cause the extoxide can substract the atoms of hydrogens from either the carbon of the cycle or the terminal methyl of the molecule and will form two different products of elimination. The product formed in greater quantities will be the one where the negative charge is more stable, in this case, in the primary carbon of the methyl it's more stable there, so product 1 will be formed more (See picture 2)
For question 6b, same principle of 6a, when the hydrogen migrates to the 2nd carbocation to form a tertiary carbocation the methanol will promove an E1 reaction with the vecinal carbons and form two eliminations products. See picture 2 for mechanism of reaction.
We know that Molarity = # mol/L
In the question, we are given grams - so we need to calculate the number of moles that we are dealing with. We can do this by first finding out what the molecular formula of calcium hydroxide is:
This means that we have 1 calcium and 2 hydroxides.
We can find the number of moles by taking the grams given divided by the molar mass of the molecule. We can find the molar mass of the molecule by taking each atomic mass of each atom (found on the periodic table) and adding them together:
Ca = 40.08g
O = 15.999g
H = 1.008g
We have 1 calcium, 2 oxygens, and 2 hydrogens. So let's add the atomic masses together:
40.08 + 2(15.999) + 2(1.008) = 74.094g
Now that we have the molar mass, we can find the number of moles due to already knowing the given amount in the question:
54.21g/74.09g = 0.73 moles of
Now that we know the number of moles, we can solve for the molarity; The other part of the question gives us 560 mL of water - but this can quickly be converted to liters by moving the decimal to the left 3 places => 0.560 L
Knowing all of this information, we can plug it into the molarity equation:
Molarity = 0.73 mol/0.56 L
Molarity = 1.30
The molarity of the solution is 1.3 M.
In the question, we are given grams - so we need to calculate the number of moles that we are dealing with. We can do this by first finding out what the molecular formula of calcium hydroxide is:
This means that we have 1 calcium and 2 hydroxides.
We can find the number of moles by taking the grams given divided by the molar mass of the molecule. We can find the molar mass of the molecule by taking each atomic mass of each atom (found on the periodic table) and adding them together:
Ca = 40.08g
O = 15.999g
H = 1.008g
We have 1 calcium, 2 oxygens, and 2 hydrogens. So let's add the atomic masses together:
40.08 + 2(15.999) + 2(1.008) = 74.094g
Now that we have the molar mass, we can find the number of moles due to already knowing the given amount in the question:
54.21g/74.09g = 0.73 moles of
Now that we know the number of moles, we can solve for the molarity; The other part of the question gives us 560 mL of water - but this can quickly be converted to liters by moving the decimal to the left 3 places => 0.560 L
Knowing all of this information, we can plug it into the molarity equation:
Molarity = 0.73 mol/0.56 L
Molarity = 1.30
The molarity of the solution is 1.3 M.