Answer:
The substance that remained on the filter paper is Al(OH).
Explanation:
- Filter paper is the substance that is used in laboratory to separate the solid objects. It doesn't filter aqueous and gaseous products.
- So in our experiment the product formed is aluminum hydroxide Al(OH) and sodium chloride (NaCl).
- Between two products, sodium chloride is in aqueous form as indicated in the question. So it wont remain in the filter paper.
- Hence aluminum hydroxide being only solid product remains on the filter paper.
The scientific notation of 420,000 is : 4.2 x 10 ^ 5
The temperature change if 400 J of energy is added to 10 grams of water is 9.57°C.
<h3>How to calculate temperature change?</h3>
The temperature change of a calorimeter can be calculated using the following expression:
E = mc∆T
Where;
- E = energy in joules
- m = mass
- c = specific heat capacity = 4.18J/g°C
- ∆T = change in temperature
400 = 10 × 4.18 × ∆T
400 = 41.8∆T
∆T = 400/41.8
∆T = 9.57°C
Therefore, the temperature change if 400 J of energy is added to 10 grams of water is 9.57°C.
Learn more about change in temperature at: brainly.com/question/11464844
In NaMnO₄, Mn has the highest oxidation number.
The question is incomplete, the complete question is;
Which of the following species contains manganese with the highest oxidation number?
A) Mn
B) MnF₂
C) Mn₃(PO₄)₂
D) MnCl₄
E) NaMnO₄
In order to ascertain the specie that contains manganese with the highest oxidation number, we must calculate the oxidation number of manganese in each of the species one after the other.
1) For Mn, the oxidation number of Mn is zero because the atom is uncombined.
2) For MnF₂;
Mn has an oxidation number of +2
3) For Mn₃(PO₄)₂
Mn has an oxidation number of +2
4) For MnCl₄
Mn has an oxidation number of +4
5) For NaMnO₄
Mn has an oxidation number of +7
Hence in NaMnO₄, Mn has the highest oxidation number.
Learn more: brainly.com/question/10079361
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