Question

38.0 mL of a 0.026 M solution of HCl is needed to react completely with a 0.032 M NaOH solution. Calculate the number of moles of HCl originally present

Answer 1

Answer:

The number of moles  of HCl actually present is 0.000988

Explanation:

The balanced chemical equation of the given reaction is

$HCl+NaOH \rightarrow NaCl+H_2 O$

Here one mole of HCl reacts with one mole of NaOH to form one mole of NaCl and one mole of  water. Here the molarity of HCl is given as 0.026M.

molarity of NaOH is 0.032M

molarity is the number of moles per unit volume of solution.

we have to calculate the number of moles in 36 mL of HCl.

38 mL=36/1000=0.038L

the number of moles in 38 mL of HCl is given by

no of moles =$0.026 \times 0.038=0.000988$