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Strike441 [17]
2 years ago
5

Someone please help me on this question! It would mean a lot! Thank you so much!

Mathematics
2 answers:
Lostsunrise [7]2 years ago
7 0
The answer is C. 15 because 1 plus 1 equals 2. subtract that by 32 and you get 30. now divid that by 2 and you have 15.
padilas [110]2 years ago
4 0
The width of the rectangle is A. 4 inches
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Factor 28+56t+28w28+56t+28w28, plus, 56, t, plus, 28, w to identify the equivalent expressions. Choose 2 answers:
Effectus [21]

Answer: The factorization of  28+56t+28w =28(1+2t+w)

The factors of 28+56t+28w are 28 and 1+2t+w.

Step-by-step explanation:

The given expression : 28+56t+28w

To factorize it, we need to find the common factor.

As 56 can be written as 2 x 28.

So, the above expression would become

28+2\times28t+28w

Now, taking 28 as common from all the terms, we will get

28(1+2t+w)

Thus, the factorization of  28+56t+28w =28(1+2t+w)

And the factors of  28+56t+28w are 28 and 1+2t+w.

6 0
3 years ago
What’s the answer to this plssss??
Murljashka [212]

I ain't gonna explain how I got to this cuz I'm quite tired rn but trust me the answer is 2c²

4 0
2 years ago
Read 2 more answers
-4(4-4v)-v=-2(-5v-2) answer
nalin [4]

Answer:

Step-by-step explanation:

-16-16v - v = 10v + 4

Add 16 to both sides and combine like terms giving you

15v = 10v + 20

Subtract 10v from both sides

5v= 20

Divide by 5

V=4

3 0
3 years ago
Read 2 more answers
Need help on this
Stolb23 [73]
15.12m2 just finished the test
4 0
3 years ago
Compute the loss of head and pressure drop in 200 ft of horizontal 6-in diameter asphalted cast iron pipe carrying water with a
laiz [17]

Answer:

The answer is below

Step-by-step explanation:

12 inches = 1 ft.

6 inches = 6 inches * (1 ft./12 inches) = 0.5 ft.

Therefore the diameter of the cast iron (D) = 6 inches = 0.5 ft.

The area of cast iron (A) = πD²/4 = π(0.5)²/4 = 0.196 ft²

The velocity (V) = 6 ft./s, the acceleration due to gravity (g) = 32.2 ft./s²

ε/D = 0.0004 ft./ 0.5 ft. = 0.0008

Using the moody chart, find the line ε/D = 0.0008 and determine the point of intersection with the vertical line R = 2.7 * 10⁵. Hence we get f = 0.02.

The head loss (h) is:

h_f=f*\frac{L}{d}* \frac{V^2}{2g}=0.02*\frac{200\ ft}{0.5\ ft} *\frac{(6\ ft/s)^2}{2*32.2\ ft/s^2}=4.5\ ft

The pressure drop (Δp) is:

Δp = ρgh_f = (62.4\ lbf/ft^3)(4.5\ ft)= 280\ lbf/ft^2

5 0
3 years ago
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