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Hey there!
For this problem, I would assume that you must make your own chart of values. You can do this by simply plugging in numbers like 1, 2, 3, etc... Since your graph won't be linear, you might want to do some negative numbers, as well.
Also because your graph isn't linear, you might want to figure out or determine on your own just how far your curve will go. You can then figure out how many times you need to plug in an additional numbers for your function to then graph.
I've attached a digital graph of this function, perhaps you can find it useful.
Hope this helped you out! :-)
For this problem, I would assume that you must make your own chart of values. You can do this by simply plugging in numbers like 1, 2, 3, etc... Since your graph won't be linear, you might want to do some negative numbers, as well.
Also because your graph isn't linear, you might want to figure out or determine on your own just how far your curve will go. You can then figure out how many times you need to plug in an additional numbers for your function to then graph.
I've attached a digital graph of this function, perhaps you can find it useful.
Hope this helped you out! :-)
We have that an inverse variation in a function is given by:
We must find the value of the constant k.
To do this, we substitute the values of x1 = 12, y1 = 15.
We have then:
Clearing k we have:
Substituting the value of k we have that the inverse variation is:
For y2 = 3 we have:
Clearing x2 we have:
Answer:
We must find the value of the constant k.
To do this, we substitute the values of x1 = 12, y1 = 15.
We have then:
Clearing k we have:
Substituting the value of k we have that the inverse variation is:
For y2 = 3 we have:
Clearing x2 we have:
Answer: