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zimovet [89]
3 years ago
8

Find the volume (in terms of pi) of a sphere if it’s surface area of 400pi ft squared

Mathematics
1 answer:
stepladder [879]3 years ago
7 0

\bf \textit{surface area of a sphere}\\\\ SA=4\pi r^2~~ \begin{cases} r=radius\\ \cline{1-1} SA=400\pi \end{cases}\implies 400\pi =4\pi r^2 \implies \cfrac{\stackrel{100}{~~\begin{matrix} 400\pi \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~} }{~~\begin{matrix} 4\pi \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}=r^2 \\\\\\ 100=r^2\implies \sqrt{100}=r\implies 10=r \\\\[-0.35em] ~\dotfill

\bf \textit{volume of a sphere}\\\\ V=\cfrac{4\pi r^3}{3}\qquad \implies V=\cfrac{4\pi (10)^3}{3}\implies V=\cfrac{4000\pi }{3}\implies V\approx 4188.79

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Can someone help me with these and show the work also?
Snezhnost [94]

QUESTION:

Simplify each expression

ANSWER:

1.) \green{{- 8n}}

2.) \green{{- 2b - 60}}

3.) \green{{- 10x - 14}}

4.) for number 4 study my step-by-step explanation so you can answer that

STEP-BY-STEP EXPLANATION:

1.) First, If the term doesn't have a coefficients, it is considered that the coefficients is 1

WHY?

Learn why:

Why is it considered that the coefficient is 1?

Remember that any term multiplied by \blue{{1}} remains the same :

\blue{{1}} {× x = x}

Step 1:

The equality can be read in the other way as a well, so any term can be written as a product of \blue{{1}} and itself:

{x = } \blue{{1}} {× x}

Step 2:

Usually, we don't need to write multiplacation sign between the coefficient and variable, so the simple form is:

{x = 1x}

This is why we can write the term without the coefficient as a term with coefficient {1}

Now let's go back to solving as what i said if a term doesn't have a coefficient, it is considered that the coefficient is 1

{n - 9n}

\red{{1}} {n -9n}

Second, Collect like terms by subtracting their coefficients

\red{{1n - 9n}}

\red{{( 1 - 9)n}}

Third, Calculate the difference

how?

Keep the sign of the number with the larger absolute value and subtract the smaller absolute value from larger

\red{{1 - 9}}

\red{{- (9 - 1)}}

Subtract the numbers

- (\red{{9 - 1}})n

- \red{{8}}n

\green{\boxed{- 8n}}

2.) First, Distribute - 6 through the parentheses

how?

Multiply each term in the parentheses by - 6

\red{{- 6(b + 10)}}

\red{{- 6b - 6 × 10}}

Multiply the numbers

- {6b} - \red{{6 × 10}}

- {6b} - \red{{60}}

Second, Collect like term

how?

Collect like terms by calculating the sum or difference of their coefficient

\red{{- 6b + 4b}}

\red{{(- 6 + 4)b}}

Calculate the sum

\red{{(- 6 + 4)}}b

\red{{-2}}b

\green{\boxed{- 2b - 60}}

3.) First, Distribute 2 through parentheses

how?

Multiply each term in the parentheses by 2

\red{{2(x - 5)}}

\red{{2x - 2 × 5}}

Multiply the numbers

{2x -} \red{{2 × 5}}

{2x -} \red{{10}}

Second, Distribute - 4 through the parentheses

how?

Multiply each term in the parentheses by - 4

\red{{- 4(3x + 1)}}

\red{{- 4 × 3x - 4}}

Calculate the product

- \red{{4 × 3}}x - 4

- \red{{12}}x - 4

Third, Collect like terms

how?

Collect like terms by subtracting their coefficient

\red{{2x - 12x}}

\red{{(2 - 12)x}}

Calculate the difference

\red{{(2 - 12)}}x

\red{{- 10}}x

Fourth, Calculate the difference

how?

Factor out the negative sign from the expression

\red{{- 10 - 4}}

\red{{- (10 + 4)}}

Add the numbers

- (\red{{10 + 4}})

- \red{{14}}

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That's all I know sorry but I hope it helps :)

6 0
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