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zubka84 [21]
3 years ago
15

A soccer team played 28 games and won 4 out of every 7 games. There are no ties.

Mathematics
1 answer:
Andrej [43]3 years ago
8 0
16 games they won in total 28 ÷7 is 4 and they won 4 games in each 7 games so 4 times 4 is 16
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A used car dealer sells SUVs and cars. Of all the vehicles, 85% are cars. Of all the vehicles, 32% are red cars. What is the pro
oksian1 [2.3K]

Answer:

37.6%

Step-by-step explanation:

P(A|B) = P(A and B) / P(B)

P(red | car) = P(red and car) / P(car)

P(red | car) = 0.32 / 0.85

P(red | car) = 0.376

8 0
3 years ago
Discrete R.V. Assume a student shows up for EGR 280 completely unprepared and the instructor gives a pop quiz. Assume there are
Tom [10]

Answer:

a) p=0.2

b) probability of passing is 0.01696

.

c) The expected value of correct questions is 1.2

Step-by-step explanation:

a) Since each question has 5 options, all of them equally likely, and only one correct answer, then the probability of having a correct answer is 1/5 = 0.2.

b) Let X be the number of correct answers. We will model this situation by considering X as a binomial random variable with a success probability of p=0.2 and having n=6 samples. We have the following for k=0,1,2,3,4,5,6

P(X=k) = \binom{n}{k}p^{k}(1-p)^{n-k} = \binom{6}{k}0.2^{k}(0.8)^{6-k}.

Recall that \binom{n}{k}= \frac{n!}{k!(n-k)!} In this case, the student passes if X is at least four correct questions, then

P(X\geq 4) = P(X=4)+P(X=5)+P(X=6)=\binom{6}{4}0.2^{4}(0.8)^{6-4}+\binom{6}{5}0.2^{5}(0.8)^{6-5}+\binom{6}{6}0.2^{6}(0.8)^{6-6}= 0.01696

c)The expected value of a binomial random variable with parameters n and p is E[X] = np. IN our case, n=6 and p =0.2. Then the expected value of correct answers is 6\cdot 0.2 = 1.2

5 0
4 years ago
Situation:
FromTheMoon [43]

Answer:

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Step-by-step explanation:

We are given;

Initial Mass; N_o = 25 g

Mass at time(t); N_t = 25/2 = 12.5 (I divide by 2 because we are dealing with half life)

k = 0.1229

Formula is given as;

N_t = N_o•e^(-kt)

Plugging in the relevant values;

12.5 = 25 × e^(-0.1229t)

e^(-0.1229t) = 12.5/25

e^(-0.1229t) = 0.5

(-0.1229t) = In 0.5

-0.1229t = -0.6931

t = -0.6931/-0.1229

t = 5.6 days

4 0
3 years ago
Help!!! Due in 10 minutes!!!!
omeli [17]
I added 40 and 120 to get 160. i devided 160 by the 6.25 she earned and got 25.6. then i rounded up to 26 hours which is the least amount of hours she could’ve worked.
5 0
3 years ago
Please help me this is for a grade and i rly need this ! :(
Iteru [2.4K]

Answer:

y=1/2x-3

Step-by-step explanation:

8 0
3 years ago
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