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2 years ago

How many liters of pure acid must be added to 3 liters of a 50% acid solution to obtain a 75%acid solution?

1 answer:

7 0

.75(x+3)=.5(3)+x

 You already have 3 liters, and you are going to add x liters.

50% (.5) of the 3 liters is acid, and 100% (1) of the added x liters is acid. You will end up with (3+x) liters.

If you have been assigned this problem, you should be able to solve this equation...

 Hope this helps you solve this, and remember how to do others like it.

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An artist is cutting pieces of ribbon to use in a project. Each piece he cuts measures

skad [1K]

Answer:

the artist cuts off 10 inches of ribbon in total

Step-by-step explanation:

2.5 × 4 = 10

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2 years ago

$22.40 is the price you pay the discount is 30% what is the original amount?

Dmitriy789 [7]

30% of 22.40 is 6.72. 6.72 plus 22.40 is 29.12. Therefore the answer is 29.12.

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2 years ago

How can you determine whether a rational number will have a terminating or a repeating decimal

Alex787 [66]

Answer:

You can determine this by putting the rational numbers in decimal form.

Step-by-step explanation:

A rational number like 1/2 will have a terminating decimal answer = 0.5

A rational number like 7/11 will have a terminating decimal answer = 0.636 where 36 is repeating.

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2 years ago

HELP

musickatia [10]

1 because it is reveresed

7 0

2 years ago

Read 2 more answers

Hi! I have a question and I don't understand it's answer. Could you help me?It's in the attachment below.

Paladinen [302]

To solve this question, we just need to evaluate our set of points in the standard form equation of a Hyperbola, and find the coefficients. This will give to us the equation for our Hyperbola. The standard form is

$\frac{(x-h)^2}{a^2}-\frac{(y-k)^2}{b^2}=1$

Let's start with the easier points, the x-intercepts (5, 0) and (-1, 0).

Since this hyperbola has two x-intercepts, we're dealing with a horizontal hyperbola, and the center is the midpoint between the x-intercepts.

$\begin{gathered} \bar{x}=\frac{x_1+x_2}{2}=\frac{-1+5}{2}=2 \\ \bar{y}=\frac{y_1+y_2}{2}=\frac{0+0}{2}=0 \end{gathered}$

The center coordinates are (2, 0), then, our equation is

$\frac{(x-2)^2}{a^2}-\frac{y^2}{b^2}=1$

To find the missing coefficients, we can just substitute the remaining points and solve the system for a and b. Our final equation is

$\frac{(x-2)^2}{9^{}}-\frac{y^2}{4}^{}=1$

6 0

1 year ago