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xxTIMURxx [149]
3 years ago
12

How is ur finger related to the parallax stars

Physics
1 answer:
yaroslaw [1]3 years ago
7 0
Bc they look the same from a farther distance
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On March 21, a stick casts the following shadow. What is the most likely time of day?
jenyasd209 [6]

Answer:

9:00 AM

Explanation:

I took the test and that was the answer

5 0
4 years ago
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Which type of communications equipment functions as a radio receiver and searches across several frequencies?
krok68 [10]

A <u>scanner</u> is a type of communications equipment that functions as a radio receiver and searches across several frequencies.

A scanner is a kind of a radio receiver that has the ability to receive multiple signals.

There are three modes which a scanner uses for acting as a radio receiver. The scan mode of the radio receiver constantly changes frequencies that helps in transmissions. There is also a manual scan mode that allows the users to search for their interested frequencies. The search mode allows the users to search through two sets of frequencies.

A scanner is a type of communication equipment that is easy to use with various features such as the volume, numeric keypad,  trunk tracking etc.

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7 0
2 years ago
What is formula of baking soda.​
Anika [276]

NaHCO3

That is the formula for baking soda

6 0
3 years ago
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A block with a mass of 9.00 kg is pulled at a constant speed across a horizontal tabletop with a spring scale. The scale reads 6
snow_tiger [21]

Answer:0.69

Explanation:

Coefficient of kinetic friction=f/R=61.8/90=0.69

7 0
3 years ago
A 1.0-kg block of aluminum is at a temperature of 50°C. How much thermal energy will it lose when its temperature is reduced by
Marat540 [252]

Answer:

22425 J

Explanation:

From the question,

Applying

Q = cm(t₂-t₁).................. Equation 1

Where Q = Thermal Energy, c = specific heat capacity of aluminium, m = mass of aluminium, t₂ = Final Temperature, t₁ = Initial Temperature.

Given: c = 897 J/kg.K, m = 1.0 kg, t₁ = 50 °C, t₂ = 25 °C (The final temperature is reduced by half)

Substitute these values into equation 1

Q = 897×1×(25-50)

Q = 897×(-25)

Q = -22425 J

Hence the thermal energy lost by the aluminium is 22425 J

5 0
3 years ago
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