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Lostsunrise [7]
4 years ago
9

Atoms of sg are very unstable, and it is therefore difficult to study this element's properties. based on the position of sg in

the periodic table, what element should it most closely resemble in its chemical properties?
Chemistry
1 answer:
ale4655 [162]4 years ago
4 0
All " transuranium elements " ( i.e. an atomic number greater than 92 ) are unstable. Elements in the same family have similar properties. Based on this logic, one would expect seaborgium ( Sg ) to have similar properties to tungsten ( W ), which is directly above it in the same family.Elements of atomic mass 92 and above being most unstable called the transuranium group of elements is found to have many common properties and becomes difficult to judge on the basis of properties. Atomic number is the number of protons in the nucleus of the atom and it describes the chemical property of the elements.
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What is a coordinate covalent bond?
Mnenie [13.5K]

Answer:

option A is correct a bond formed by transfer of electron

4 0
4 years ago
Calculate moles of 3.9g of sodium
Vesnalui [34]

Answer:

\boxed{\text{0.17 mol}}

Explanation:

\text{M$_{r}$ of Na} = 22.99\\\text{Moles} = \text{3.9 g } \times \dfrac{\text{1 mol}}{\text{22.99 g}} = \text{0.17 mol}\\\\\text{ The sample contains $\boxed{\textbf{0.17 mol}}$ of Na}

4 0
3 years ago
A sample of an Iron Oxalato complex salt weighting 0.145 grams requires 34.88 mL of 0.015 M KMnO4 to turn the solution a very li
Amanda [17]

Answer:

5.2 ×10^-4 moles

Explanation:

Equation of reaction:

5C2O4^2- + 2MnO4^- +. 6H^+. ----------> 10CO2. +. 8H2O. + 2Mn^2+

From the information provided in the question:

Volume of potassium permanganate= 34.88ml

Concentration of potassium permanganate= 0.015M

Amount potassium permanganate= 0.015 × 34.88/1000= 5.2 ×10^-4 moles

6 0
4 years ago
Read 2 more answers
If a solution containing 94.28 g of mercury(II) acetate is allowed to react completely with a solution containing 16.642 g of so
STatiana [176]

Answer:

68.83 g HgS

Explanation:

The balanced reaction is:

Hg(C₂H₃O₂)₂ + Na₂S  ---> 2 NaC₂H₃O₂ + HgS

Because Hg(C₂H₃O₂)₂ reacts completely, it is the limiting reactant. The solid precipitate is mercury (II) sulfide.

To find the amount of solid precipitate, you need to (1) convert grams Hg(C₂H₃O₂)₂ to moles Hg(C₂H₃O₂)₂ (via molar mass from periodic table), then (2) convert moles Hg(C₂H₃O₂)₂ to moles HgS (via mole-to-mole ratio from reaction coefficients), and then (3) convert moles HgS to grams HgS (via molar mass from periodic table).

It is important to arrange the ratios/conversions in a way that allows for the cancellation of units. The desired unit should be the numerator. The final answer should have 4 sig figs because the given value with the lowest sig fig value (94.28 grams) has 4 sig figs.

Molar Mass (Hg(C₂H₃O₂)₂): 200.59 g/mol + 4(12.01 g/mol) + 6(1.008 g/mol) + 4(16.00 g/mol)

Molar Mass (Hg(C₂H₃O₂)₂): 318.678 g/mol

Molar Mass (HgS): 200.59 g/mol + 32.07 g/mol

Molar Mass (HgS): 232.66 g/mol

94.28 g Hg(C₂H₃O₂)₂           1 mole                 1 mole HgS                232.66 g
-------------------------------  x  ------------------ x ------------------------------  x  ----------------  =
                                           318.678 g        1 mole Hg(C₂H₃O₂)₂         1 mole

=  68.83 g HgS

5 0
2 years ago
Blair bought a hutch for her desk that was 23 inches long. The box said that the
arlik [135]
Percent error = observed - true/true * 100, observed = 23, true = 25
23-35 = -2/25 = -0.08 = 8% error
I think (or I might had reversed the observed and true)
4 0
3 years ago
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