Answer:
A. 1s²2s²
B. 1s²
C. 1s²
D. 1s²2s²2p⁶
Explanation:
The valency electron is the outer electron of an element. The valency electron resides in the outermost region of the shell.
Using the general configuration for the first 20 elements 2 8 8 2 the valency electrons can be identified.
A. 1s²2s²2p⁶3s² . The valency electron here are 2p⁶ and 3s² . Removing the valency electron we have 1s²2s²
B. 1s² 2s² 2p⁶. After removing the valency electron the configuration will be 1s².
C.1s²2s². After removing the valency electron the configuration will be 1s²
D.1s²2s²2p⁶3s¹. Removing the valency electron the electron configuration will be 1s²2s²2p⁶
Answer:
1.78
Explanation:
1mole produce 18g/x will produce 32g then the answer is 1.78moles
Answer:
C3H6 + Br2 → C3H6Br2
Explanation:
The reaction in which C3H6Br2 (1,2-Dibromopropane) is created is:
We can see that the only difference between the product (C3H6Br2) and the known reactant (C3H6) of the reaction is two bromine atoms (Br2). Br2 is diatomic bromine - a molecule we get after combining two bromine atoms. This compound is a red-brown liquid at room temperature, which means that that is the liquid described in your question.
Answer:
I think it might be C
Explanation:
Im not sure though
Please tell me if im wrong