Question

A sample of an Iron Oxalato complex salt weighting 0.145 grams requires 34.88 mL of 0.015 M KMnO4 to turn the solution a very light pink color at the quivalence point. Calculate the number of moles of KMnO4 added.

Answer 1

Answer:

5.2 ×10^-4 moles

Explanation:

Equation of reaction:

5C2O4^2- + 2MnO4^- +. 6H^+. ----------> 10CO2. +. 8H2O. + 2Mn^2+

From the information provided in the question:

Volume of potassium permanganate= 34.88ml

Concentration of potassium permanganate= 0.015M

Amount potassium permanganate= 0.015 × 34.88/1000= 5.2 ×10^-4 moles

Answer 2

Answer:

5.232x10⁻⁴ moles added

Explanation:

Potassium permanganate (KMnO₄) is a salt widely used in chemical industry, medicine and laboratories such as other places as a strong oxidizing agent.

A 0.015M KMnO₄ contains 0.015 moles per liter of solution. Liters in 34.88mL are:

34.88mL ₓ (1L / 1000mL) = 0.03488L. Thus, moles added are:

0.03488L ₓ (0.015 moles / 1L) = 5.232x10⁻⁴ moles added