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Gelneren [198K]
3 years ago
5

A sample of an Iron Oxalato complex salt weighting 0.145 grams requires 34.88 mL of 0.015 M KMnO4 to turn the solution a very li

ght pink color at the quivalence point. Calculate the number of moles of KMnO4 added.
Chemistry
2 answers:
Amanda [17]3 years ago
6 0

Answer:

5.2 ×10^-4 moles

Explanation:

Equation of reaction:

5C2O4^2- + 2MnO4^- +. 6H^+. ----------> 10CO2. +. 8H2O. + 2Mn^2+

From the information provided in the question:

Volume of potassium permanganate= 34.88ml

Concentration of potassium permanganate= 0.015M

Amount potassium permanganate= 0.015 × 34.88/1000= 5.2 ×10^-4 moles

romanna [79]3 years ago
4 0

Answer:

5.232x10⁻⁴ moles added

Explanation:

Potassium permanganate (KMnO₄) is a salt widely used in chemical industry, medicine and laboratories such as other places as a strong oxidizing agent.

A 0.015M KMnO₄ contains 0.015 moles per liter of solution. Liters in 34.88mL are:

34.88mL ₓ (1L / 1000mL) = <em>0.03488L. </em>Thus, moles added are:

0.03488L ₓ (0.015 moles / 1L) = <em>5.232x10⁻⁴ moles added</em>

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3 years ago
Compounds A, B, and C react according to the following equation. 3A(g) + 2B(g) 2C(g) At 100°C a mixture of these gases at equili
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Answer:

The value of Kc for the reaction is 3.24

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aA + bB ⇔ cC + dD

where a, b, c and d are the stoichiometric coefficients, the equilibrium constant with the following equation:

Kc=\frac{[C]^{c} *[D]^{d} }{[A]^{a} *[B]^{b} }

Kc is equal to the multiplication of the concentrations of the products raised to their stoichiometric coefficients divided by the multiplication of the concentrations of the reagents also raised to their stoichiometric coefficients.

Then, in the reaction 3A(g) + 2B(g) ⇔ 2C(g),  the constant Kc is:

Kc=\frac{[C]^{2} }{[A]^{3} *[B]^{2} }

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3 years ago
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Answer: Option (D) is the correct answer.

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So, in order to attain stability it tends to gain one electron from a donor atom. Therefore, a chlorine ion is formed as Cl^{-1}.

As it gains only one electron that is why, -1 charge occurs.

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Thus, we can conclude that Cl is the atom which tends to gain 1 valence electron from another atom in order to become stable.

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