When a sample of CO2(s) becomes CO2(g), there a change in

Chemistry

1 answer:

KatRina [158]3 years ago

4 0

Answer:

4)Particle Arrangement

Explanation:

When solid carbon dioxide CO₂ will evaporate in gaseous carbon dioxide CO₂ the particles arrangement will change from ordered in solid state to completely disordered in gaseous state.

Bond type, gram formula mass and molecular polarity are not changed in the described physical transformation.

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Match the terms below to the correct definitions

Yakvenalex [24]

Answer:

Explanation:

1=i

4=d

5=m

6=c

8=o

9=j

10=a

13=b

14=h

15=l

Theses are the ones i knew

4 0

3 years ago

Determine the heat of reaction (ΔHrxn) for the combustion of ethanol (C2H5OH) by using heat of formation data: C2H5OH (l) + 3 O2

egoroff_w [7]

Answer:

$\Delta H_{rxn}=-1234.782kJ$

Explanation:

$\Delta H_{rxn}=\sum [n_{i}\times \Delta H_{f}^{0}(product)_{i}]-\sum [n_{j}\times \Delta H_{f}^{0}(reactant_{j})]$

Where $n_{i}$ and $n_{j}$ are number of moles of product and reactant respectively (equal to their stoichiometric coefficient).

$\Delta H_{f}^{0}$ is standard heat of formation.

So, $\Delta H_{rxn}=[2mol\times \Delta H_{f}^{0}(CO_{2})_{g}]+[3mol\times \Delta H_{f}^{0}(H_{2}O)_{g}]-[1mol\times \Delta H_{f}^{0}(C_{2}H_{5}OH)_{l}]-[3mol\times \Delta H_{f}^{0}(O_{2})_{g}]$