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expeople1 [14]
3 years ago
11

Calculate moles of 3.9g of sodium

Chemistry
1 answer:
Vesnalui [34]3 years ago
4 0

Answer:

\boxed{\text{0.17 mol}}

Explanation:

\text{M$_{r}$ of Na} = 22.99\\\text{Moles} = \text{3.9 g } \times \dfrac{\text{1 mol}}{\text{22.99 g}} = \text{0.17 mol}\\\\\text{ The sample contains $\boxed{\textbf{0.17 mol}}$ of Na}

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