Answer:
The molar heat of vaporization of dichloromethane is 30.8kJ/mole
Explanation:
Using Clausius Clapeyron equation
ln (P1/P2) = (ΔHvap/R) (1/T2-1/T1)
At initial temperature of Ooc , the vapour pressure is 134mmHg
Therefore T1 = 0+273 =273K
And P1 = 134mmHg
At normal boiling point of 40oC , the vapour pressure is 760mmhg
T2 = 40 +273 = 313K
P2 = 760mmHg
ln (134/760) = ΔHvap/(8.3145 J/molK)
( 1/313K - 1/273K)
ΔHvap = 30800J/mol
= 30.8kJ/mol
Therefore, the molar heat of vaporization can be calculated using
Clausius Clapeyron equation using the above steps
The SI base unit for amount of substance is the mole. 1 mole is equal to 1 moles Lithium, or 6.941 grams.
The term "atom" comes from the Greek word for indivisible, because it was once thought that atoms were the smallest things in the universe and could not be divided. We now know that atoms are made up of three particles: protons, neutrons and electrons — which are composed of even smaller particles, such as quarks
Answer:
The quantity of heat required to melt all the ice at 0°C is 2.21 * 10⁶ J
Explanation:
Latent heat of fusion is the heat absorbed by a unit mass of a given solid at its melting point that completely converts the solid to a liquid at the same temperature. Its unit is Joules/kg or Joules/g.
1 calorie = 4.184 Joules
Therefore , 80.0 cal/g = 80.0 cal/g * 4.184 J/cal = 334.72 J/g
1 g = 0.001 kg; Heat of fusion in J/kg = 334.72 J/g * 1g /0.001 kg = 3.35 * 10⁵ J/kg
Quantity of heat, Q = mass * latent heat of fusion of ice
quantity of heat required = 6.60 kg * 3.35 * 10⁵ J/kg
Quantity of heat required = 2.21 * 10⁶ J
Therefore, the quantity of heat required to melt all the ice at 0°C is 2.21 * 10⁶ J
Weathering and chemical substance weathering