Answer:
1. molarity is = 0.1174
2. molarity is = 9.3
3. molarity is =0.009392
Explanation:
Q#1.
mass of sucrose is 14.07g
molar mass of sucrose is 342 3g/mol
so, 14.07x1/342.3 = 0.0411
now the volume is of water is 0.35
so, 0.0411/0.35 = 0.1174
Q#2.
concentration is 4.5
so, 4.5x1/1000= 0.0045
then, 0.0411/0.0045 = 9.13
Q#3.
M1M1=M2M2
molarity of the same sucrose is 0.1174
so, diluted in 40mL
and the volumetric flask is 500mL
so, 0.1174x40/500= 0.009392
First, we have to calculate the number of moles of H2SO4 in the solution:
V=60 mL = 0.06 L
c=5.85 mol/L
n=V×c=0.06×5.85=0.351 mol
Then we need to find the molar mass of H2SO4:
2×Ar(H) + Ar(S) + 4×Ar(O) =
=2 + 32 + 64 = 98 g/mol
Finally, we need to find the mass of H2SO4:
m=0.351 × 98 = 34.398 g
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Answer:
A compound contains atoms of different elements chemically combined together in a fixed ratio. An element is a pure chemical substance made of same type of atom.
