All categories

2 years ago

10. Air is a homogenous mixture of gases. Oxygen is 20% by volume of air typically. What

Chemistry

1 answer:

raketka [301]2 years ago

3 0

Answer:

893 moles

Explanation:

An ideal gas at STP occupies 22.4 liters. Calculating Oxygen as if it were an ideal gas there are . 893 moles of Oxygen in 20.0 liters.

You might be interested in

Determine the molecular

jeyben [28]

Answer:

MgO- magnesium oxide

Cu(NO3)2- copper(11)nitrate

Li2CO3- lithium carbonate

7 0

2 years ago

How do solve for #13?What is the boiling point of a solution made by dissolving 1.0000 mole of sucrose in 1.0000 kg of water?

exis [7]

What is the boiling point of a solution made by dissolving 1.0000 mole of sucrose in 1.0000 kg of water?

The change in Boiling Point of water can be calculated using this formula:

ΔTb = i * Kb * m

Where i is the van't hoff factor (the number of particles or ions), the kb is a constant (boiling point elevation constant) and m is the molality of the solution.

The kb for water is always 0.515 °C/m. Kb = 0.515 °C/m

The value for i in this case is 1. Since sucrose is a covalent compound and it doesn't dissociate into ions. i = 1

The molal concentration of the solution can be found using this formula:

molality = moles of sucrose/kg of water

molality = 1.000 mol / 1.000 kg of water

molality = 1 m

Now that we know all the values, we can use the formula to find the change in the boiling point of water:

ΔTb = i * Kb * m

ΔTb = 1 * 0.515 °C/m * 1 m

ΔTb = 0.515 °C

Finally, we are asked for the boiling point of the solution, not the change. The boiling point of water at atmospheric pressure is 100.00 °C. If the boiling point rises 0.515 °C when we prepare the solution. The boiling point of the solution is:

Boiling point solution = Boiling point of water + ΔTb

Boiling point solution = 100.000 °C + 0.515 °C

Boiling point solution = 100.515 °C

Answer: The boiling point of the solution is 100.515 °C.

8 0

8 months ago

If one iron nail weighs 2.0 grams, what would be the mass of 6.022 x 10^23 nails?

Maru [420]

Answer:

$1.2x10^{24}g$

Explanation:

Hello!

In this case, it is possible to treat this problem by using a proportional factor which indicates one iron nail equals 2.0 grams:

$\frac{2.00g}{1nail}$

Now, for an amount of 6.022x10²³ nails, the corresponding mass will be:

$6.022x10^{23}nail*\frac{2.00g}{1nail} \\\\1.2x10^{24}g$

Best regards!

8 0

2 years ago

Nuclear Chemistry Writing Assignment

pogonyaev

Answer:

21 years

% of parent isotope remaining before safe

6.25%

Explanation:

6 0

2 years ago

Read 2 more answers

A chemist has a 2.0 M solution of copper (II) sulfate. Is he takes 400 mL of this solution and dilutes it with 1200 mL of water,

Ksenya-84 [330]

0.66 M is the accurate molarity of the new solution of volume of 1200 ml.

Explanation:

Data given:

molarity of copper(II) sulphate, Mconc.= 2M

volume of 2M solution taken Vconc. = 400 ml

volume taken for dilution, Vdilute = 1200 ml

molarity of the diluted solution, Mdilute =?

We will use the formula for dilution as

Mconc Vconc = Mdilute x V dilute (conc is concentrated)

putting the values in the equation:

2 x 400 = Mdilute x 1200

Mdilute = $\frac{800}{1200}$

Mdilute = 0.66 M

When the solution is diluted to the volume of 1200 ml its molarity changes to 0.66 M.

4 0

3 years ago