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4 years ago

14

Neil has three partial full cans of white paint they contains 1/3 gallon 1/5 gallon 1/2 gallon of paint and how much paint does

Niall have in all

1 answer:

podryga [215]4 years ago

5 0

Answer:

1 and 1/30 gallons of paint

Step-by-step explanation:

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Please help I’m so confused Find: cos A

kobusy [5.1K]

Answer:15/17

Step-by-step explanation:

8 0

3 years ago

The sum of the interior angles of a hexagon is _____.

kupik [55]

<span>The sum of the interior angles of a hexagon is 720

In short, Your Answer would be Option D

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5 0

3 years ago

Read 2 more answers

A right-angled triangle has shorter side lengths exactly c^2-b^2 and 2bc units respectively, where b and c are positive real num

yKpoI14uk [10]

Answer: hypotenuse = $c^{2} + b^{2}$

Step-by-step explanation: Pythagorean theorem states that square of hypotenuse (h) equals the sum of squares of each side ( $s_{1},s_{2}$ ) of the right triangle, .i.e.:

$h^{2} = s_{1}^{2} + s_{2}^{2}$

In this question:

$s_{1}$ = $c^{2}-b^{2}$

$s_{2} =$ 2bc

Substituing and taking square root to find hypotenuse:

$h=\sqrt{(c^{2}-b^{2})^{2}+(2bc)^{2}}$

Calculating:

$h=\sqrt{c^{4}+b^{4}-2b^{2}c^{2}+(4b^{2}c^{2})}$

$h=\sqrt{c^{4}+b^{4}+2b^{2}c^{2}}$

$c^{4}+b^{4}+2b^{2}c^{2}$ = $(c^{2}+b^{2})^{2}$ , then:

$h=\sqrt{(c^{2}+b^{2})^{2}}$

$h=(c^{2}+b^{2})$

Hypotenuse for the right-angled triangle is $h=(c^{2}+b^{2})$ units

3 0

3 years ago

A test grade was 92%. 60 items were correct. How many test items were there?

Anna11 [10]

Set up an inequality:

$\frac{92}{100}$ = $\frac{60}{x}$

Cross-multiply:
92x=6000
x=65 questions

6 0

3 years ago

A: {71,73,79,83,87} B:{57,59,61,67}

Jobisdone [24]

Answer:

$\frac{3}{5}$ .

Step-by-step explanation:

We have been given two sets as A: {71,73,79,83,87} B:{57,59,61,67}. We are asked to find the probability that both numbers are prime, if one number is selected at random from set A, and one number is selected at random from set B.

We can see that in set A, there is only one non-prime number that is 87 as it is divisible by 3.

So there are 4 prime number in set A and total numbers are 5.

$P(\text{Prime number from A})=\frac{4}{5}$

We can see that in set B, there is only one non-prime number that is 57 as it is divisible by 3.

So there are 3 prime number in set B and total numbers are 4.

$P(\text{Prime number from B})=\frac{3}{4}$

Now, we will multiply both probabilities to find the probability that both numbers are prime. We are multiplying probabilities because both events are independent.

$P(\text{Prime number from A and B})=\frac{4}{5}\times \frac{3}{4}$

$P(\text{Prime number from A and B})=\frac{1}{5}\times \frac{3}{1}$

$P(\text{Prime number from A and B})=\frac{3}{5}$

Therefore, the probability that both numbers are prime would be $\frac{3}{5}$ .

4 0

3 years ago