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leva [86]
3 years ago
6

EASY FOR THE RIGHT PERSON! TONS OF POINTS! Write these functions as numbers instead of words

Mathematics
1 answer:
Elena L [17]3 years ago
3 0
A. f(b) = 3+b

b. f(x) = (x+3)²

c. f(x) = (x+3)/(12-x)

d. f(x) = x⁵-4x+6

e. f(x) = -45

f. f(x) = x
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Simplify 2(-3x -6) I want to simplify it but I'm not sure how
Gelneren [198K]

Answer:

-6x-12

Step-by-step explanation:

2(-3x-6)

Multiply: 2(-3x)+2(-6)

so answer is -6x-12

4 0
3 years ago
Read 2 more answers
17. If a triangle has sides of 21 and 36, what is the range for the shortest side?
Leona [35]
Given a = 7 and b = 13, this gives us for c:

6 < c < 20, i maybe be wrong
6 0
3 years ago
A rainwater collection tank is shaped like a cylinder with a diameter of 4 ft and height of 6 ft what is its volue
lana [24]
Volume = π×22<span>×6 = </span><span>75.398223686155 feet^3</span>
6 0
3 years ago
What is the equation of a line that passes through the points (-3, 4) and (2,8)?
ziro4ka [17]

Given that the line passes through the two points (-3,4) and (2,8)

We need to determine the equation of the line.

<u>Slope:</u>

The slope of the line can be determined using the formula,

m=\frac{y_2-y_1}{x_2-x_1}

Substituting the points (-3,4) and (2,8) in the above formula, we get;

m=\frac{8-4}{2+3}

m=\frac{4}{5}

Thus, the slope of the line is m=\frac{4}{5}

<u>Equation of the line:</u>

The equation of the line can be determined using the formula,

y-y_1=m(x-x_1)

Substituting the point (-3,4) and m=\frac{4}{5} in the above formula, we have;

y-4=\frac{4}{5}(x+3)

y-4=\frac{4}{5}x+\frac{12}{5}

     y=\frac{4}{5}x+\frac{12}{5}+4

     y=\frac{4}{5}x+\frac{32}{5}

Thus, the equation of the line is y=\frac{4}{5}x+\frac{32}{5}

6 0
3 years ago
Please Help !!!
solong [7]
Best Answer: 2 LiCl = 2 Li + Cl2
mass Li = 56.8 mL x 0.534 g/mL=30.3 g
moles Li = 30.3 g / 6.941 g/mol=4.37
the ratio between Li and LiCl is 2 : 2 ( or 1 : 1)

moles LiCl required = 4.37
mass LiCl = 4.37 mol x 42.394 g/mol=185.3 g


Cu + 2 AgNO3 = Cu/NO3)2 + 2 Ag
the ratio between Cu and AgNO3 is 1 : 2
moles AgNO3 required = 4.2 x 2 = 8.4 : but we have only 6.3 moles of AgNO3 so AgNO3 is the limiting reactant
moles Cu reacted = 6.3 / 2 = 3.15
moles Cu in excess = 4.2 - 3.15 =1.05

N2 + 3 H2 = 2 NH3
moles N2 = 42.5 g / 28.0134 g/mol=1.52
the ratio between N2 and H2 is 1 : 3
moles H2 required = 1.52 x 3 =4.56
actual moles H2 = 10.1 g / 2.016 g/mol= 5.00 so H2 is in excess and N2 is the limiting reactant
moles NH3 = 1.52 x 2 = 3.04
mass NH3 = 3.04 x 17.0337 g/mol=51.8 g
moles H2 in excess = 5.00 - 4.56 =0.44
mass H2 in excess = 0.44 mol x 2.016 g/mol=0.887 g
5 0
3 years ago
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