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3 years ago

Which relation is represented by the arrow diagram?

Mathematics

2 answers:

il63 [147K]3 years ago

6 0

I think it talks about if this is a one to one function or not

balandron [24]3 years ago

4 0

Answer:

The required relation is: {(-2,3), (0,3), (1,1), (3,4), (4,6)}

Step-by-step explanation:

Consider the provided diagram.

Here the left side represents the input (X) values and the right side represents the output (Y) values.

The -2 has an arrow pointing to 3, so this becomes (-2,3).

The 0 has an arrow pointing to 3, so this becomes (0,3).

The 1 has an arrow pointing to 1, so this becomes (1,1).

The 3 has an arrow pointing to 4, so this becomes (3,4).

The 4 has an arrow pointing to 6, so this becomes (4,6).

Hence, the required relation is: {(-2,3), (0,3), (1,1), (3,4), (4,6)}

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Eduardwww [97]

Answer: 47.4 yds.

So, if this is a right triangle then you will have a hypotenuse, opposite Leg, and the adjacent. I get it that the first Leg is X an the other is 40 and the hypotenuse is 62.

C=62

A=40

B= X

We gonna use the Pythagorean theorem to solve this problem

C^2=a^2+b^2

62^2=40^2+x^2

x^2 = (62^2) -(40^2)

x^2= 3844-1600

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3 years ago

What is 3 1/8 - 1 1/8 =

aalyn [17]

Answer:

Step-by-step explanation:

3 1/8 - 1/8 = 3

3-1 = 2

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Write 2 decimals whose product is 0.16

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A ball is chosen at random from a bag containing 150 balls that are either red or blue and either dull or shiny. There are 36 re

tino4ka555 [31]

Answer:

The probability of the chosen ball being shiny conditional on it being red is; 0.375

Step-by-step explanation:

Let A be the event that a red ball has been chosen

Let B be the event that a shiny ball has been chosen

Let S be the total outcomes = 150 balls

Thus;

P(A ∩ B ) = 36/150

A ∩ B' = 150 - 36 - 54

A ∩ B' = 60

Thus; P(A ∩ B') = 60/150

P(A') = 54/150

P(A) = (150 - 54)/150 = 96/150

Thus, probability of the chosen ball being shiny conditional on it being red is;

P(B | A) = P(B ∩ A)/P(A)

Thus; P(B | A) = (36/150)/(96/150)

P(B | A) = 0.375

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2 years ago