Answer:
59°
Step-by-step explanation:
The angles of a triangle equal 180°.
Also the angle of a straight line is 180°.
So you first find the missing bottom angle by taking 180-147 to equal 33.
Then you take 33+88+x=180
solve for x by subtracting 88 and 33 from 180 to equal 59.
Answer: True
Step-by-Step Explanation:
=> 2x + 3y = -7 (Eq. 1)
=> -x = 2y (Eq. 2)
=> x = 1, y = -3
Substitute values of ‘x’ and ‘y’ in Eq. 1 :-
=> 2x + 3y = -7
= 2(1) + 3(-3) = -7
= 2 + -9 = -7
=> -7 = -7
=> LHS = RHS
Therefore, it is a Solution.
Answer:
259.6 ft/sec
Step-by-step explanation:
it is a universal standard that acceleration due to gravity is 32ft/sec^2.
Now it can be verified by equation,
V(f) = V(i)+at (1st equation of motion derived by Newton's three laws of motion)
where,
V(f) is final velocity
V(i) is initial velocity
a is acceleration which is constant and have value 32ft/sec^2
t is time which is given as 7.8 seconds
In the given case, initial velocity that is V(i) will be 0ft/sec. Because, on dropping, object will start to move under the influence of gravity from zero speed.
So,
V(f) = 0 +(32) (7.8)
V(f) = 249.6 ft/sec
Now the condition is given that you have to add a constant 10 to the answer.
so, V(f) = 249.6 + 10
V(f) = 259.6 ft/sec
Answer:
Option (D)
Step-by-step explanation:
Length of the bar EG = 1.6x
If F is a point on the bar such that,
EF + FG = EG
Measure of segment EF = 6
Measure of FG = x
By substituting measures of each side,
6 + x = 1.6x
1.6x - x = 6
0.6x = 6
x = 10
Length of EG = x + 6
= 10 + 6
= 16 units
Option (D) will be the correct option.
Answer:
Complete the following statements. In general, 50% of the values in a data set lie at or below the median. 75% of the values in a data set lie at or below the third quartile (Q3). If a sample consists of 500 test scores, of them 0.5*500 = 250 would be at or below the median. If a sample consists of 500 test scores, of them 0.75*500 = 375 would be at or above the first quartile (Q1).
Step-by-step explanation:
The median separates the upper half from the lower half of a set. So 50% of the values in a data set lie at or below the median, and 50% lie at or above the median.
The first quartile(Q1) separates the lower 25% from the upper 75% of a set. So 25% of the values in a data set lie at or below the first quartile, and 75% of the values in a data set lie at or above the first quartile.
The third quartile(Q3) separates the lower 75% from the upper 25% of a set. So 75% of the values in a data set lie at or below the third quartile, and 25% of the values in a data set lie at or the third quartile.
The answer is:
Complete the following statements. In general, 50% of the values in a data set lie at or below the median. 75% of the values in a data set lie at or below the third quartile (Q3). If a sample consists of 500 test scores, of them 0.5*500 = 250 would be at or below the median. If a sample consists of 500 test scores, of them 0.75*500 = 375 would be at or above the first quartile (Q1).
