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Kay [80]
3 years ago
12

I need the answer as quickly as possible, please.

Mathematics
2 answers:
Luda [366]3 years ago
7 0
Your Answer is : A.
x^2 + 10x + 25
Brilliant_brown [7]3 years ago
4 0

Answer:

×^2-10× + 25

I'm not sure

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What is the area of ABC below? If necessary, round your answer to two decimal places.
irina [24]
Our goal is to find the area
area=1/2 times base times height
we know the height is 7.9 but what is the base?


use the pythagorean theorem twice
alrighty
so
remember for legs length a and b and hytponuse c in a right triangle
a²+b²=c²

we need AD and DC

so
AD²+7.9²=9.4²
AD=√25.95

DC²+7.9²=23.2²
DC=√475.83

so
AD+DC=base=(√25.95)+(√475.83)
area=1/2bh
area=1/2((√25.95)+(√475.83))(7.9)
area≈106.28518654591426812803776879893
round to 2 decimal places
area≈106.29 square units
6 0
2 years ago
Determine the m m m m m
iVinArrow [24]

Answer:

A,D,E,G=83 B,C,F=97

Step-by-step explanation:

5 0
2 years ago
A rectangular prism is 7 centimeters long, 5 centimeters wide, and 4 centimeters tall. Which values are the areas of cross secti
VladimirAG [237]
Cross section is the area you make when you make a cut across a shape. In this case, the cut must be parallel to the base. Hence, the cut shape would be same to that of the base. The base's dimensions are 7 cm long x 5 cm wide. Thus, the cross section area is 35 square centimeters.
3 0
3 years ago
Read 2 more answers
Solve 3x+2y=4 4x+3y=7 algebraically
Leona [35]
Step 1. Multiply first equation with -3 and the second one with 2. You'll get:
\left \{ {{-9x-6y=-12} \atop {8x+6y=14}} \right.

Step 2. Add both equations together. You'll get:
-x=2, which gives x = -2

Step 3. Replace x = -2 in the first equation and calculate y.
3(-2)+2y=4\\
y=\frac{4+6}{2}=5

The solution is: x=-2, y=5
8 0
3 years ago
Which quadratic function is represented by the table ???
Ulleksa [173]

Answer:

B) f(x) = 3x² - 2x + 5

Step-by-step explanation:

To find the correct quadratic function that represents the table, you must substitute [x] into the quadratic function.

A) f(x) = 3x² + 2x - 5

B) f(x) = 3x² - 2x + 5

C) f(x) = 2x² + 3x - 5

D) f(x) = 2x² - 2x + 5

A.   3(-2)² + 2(-2) - 5 =

3(4) - 4 - 5

12 -  4 - 5

12 - 9

= 3

B.   3(-2)² - 2(-2) + 5 =

3(4) + 4 + 5

12 + 9

= 21

C.   2(-2)² + 3(-2) -5 =

2(4) - 6 - 5

8 - 11

= - 3

D.   2(-2)² + 2(-2) + 5 =

2(4) - 4 + 5

8 - 4 + 5

8 + 1

= 9

Your correct answer is: B

8 0
3 years ago
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