4.) is the force of attraction or repulsion between objects 3.) is a property of most metals <span>2.) can be used to create electricity i hope this helps you</span>
Answer:
A) electric field strength between the plates;E = 2 x 10^(6) N/C
B) exit velocity;v = 8.39 x 10^(7) m/s
Explanation:
We are given;
Potential difference; V = 20 kV = 20000 V
Distance between the 2 parallel plates; d = 1cm = 0.01 m
A) The electric field strength will be gotten from;
E = V/d
E = 20000/0.01
E = 2000000
E = 2 x 10^(6) N/C
B) For exit speed, we'll use the formula for Kinetic energy; KE = (1/2)mv²
KE is also expressed as; V•q_e
Thus,
(1/2)mv² = V•q_e
Where;
V is potential difference = 20000 V
Q_e is charge of electron which has a constant value of; (1.6 x 10^(-19))C
m is mass of electron with a constant value of (9.1 x 10^(-31)) kg
v is the velocity
Thus, making v the subject, we have;
v = √((2V•q_e)/m)
v = √((2 x 20000•(1.6 x 10^(-19)))/(9.1 x 10^(-31)))
v = 83862786 m/s or
v = 8.39 x 10^(7) m/s
Answer:
34.62m/s^2
Explanation:
Force = mass x acceleration
Given
Force = 1800N
Mass = 52kg
Therefore
1800 = 52 x a
Divide both sides by 52
1800/52 = 52/52 x a
34.62 = a
a = 34.62m/s^2
Explanation:
3 cause the triangle method of addition are connected to tips of one vector