The free-body diagram of the forces acting on the flag is in the picture in attachment.
We have: the weight, downward, with magnitude

the force of the wind F, acting horizontally, with intensity

and the tension T of the rope. To write the conditions of equilibrium, we must decompose T on both x- and y-axis (x-axis is taken horizontally whil y-axis is taken vertically):


By dividing the second equation by the first one, we get

From which we find

which is the angle of the rope with respect to the horizontal.
By replacing this value into the first equation, we can also find the tension of the rope:
Answer:
D
Explanation:
The answer is Niels Bohr's planetary model, the difference between this model and all of the other models is that the Bohr's PM Is more of layers of
Nucleus - Protons and Neutrons
Electron Orbital - Period 1 Elements
2 electrons
Electron Orbital - Period 2 Elements
8 electrons
Electron Orbital - Period 3 Elements
8 electrons
If that made sense-
Answer:
The angle from vertical of the axis of the second polarizing filter is 50.57⁰.
Explanation:
Given;
intensity of the unpolarized light, I₀ = 300 W/m²
intensity of emergent polarized light, I = 121 W/m²
let the angle from vertical of the axis of the second polarizing filter = θ
Apply Malus's law, intensity of emergent polarized light is given as;
I = I₀Cos²θ

Therefore, the angle from vertical of the axis of the second polarizing filter is 50.57⁰.