All categories

3 years ago

What term is defined as the amount of charge stored per volt?

Physics

2 answers:

scoundrel [369]3 years ago

7 0

Explanation:

Capacitance of a capacitor is defined as the amount of charge stored per unit voltage. Capacitor is a device that is used to store electric charge. Its mathematical term is given by :

$C=\dfrac{Q}{V}$

Q is the amount of charge

V is the voltage or potential difference

Its SI unit is farad. It consist of two conducting plates that are separated by an insulating material. If A is the cross sectional area of each of the plates that are separated by a distance d. Then capacitance is given by :

$C=\dfrac{A\epsilon_o}{d}$

$\epsilon_o$ is the permittivity of the free space

Shtirlitz [24]3 years ago

3 0

Capacitance is a measure of charge stored per volt.

You might be interested in

The drawing shows a large cube (mass = 28.6 kg) being accelerated across a horizontal frictionless surface by a horizontal force

MrRissso [65]

Answer:

P= 454.11 N

Explanation:

Since P is the only horizontal force acting on the system, it can be defined as the product of the acceleration by the total mass of the system (both cubes).

$P= (M+m)*a\\a = \frac{P}{28.6 +4.3}\\a = \frac{P}{32.9}$

The friction force between both cubes (F) is defined as the normal force acting on the smaller cube multiplied by the coefficient of static friction. Since both cubes are subject to the same acceleration:

$F = m * a*\mu \\F= 4.3*0.710*\frac{P}{32.9}\\F=3.053*\frac{P}{32.9}$

In order for the small cube to not slide down, the friction force must equal the weight of the small cube:

$3.053*\frac{P}{32.9} = 4.3 * g\\\\P = \frac{4.3*9.8*32.9}{3.053} \\P= 454.11 N$

The smallest magnitude that P can have in order to keep the small cube from sliding downward is 454.11 N

8 0

3 years ago

What is the force felt by the electrons and the nuclei in the rod when the external field described in the problem introduction

fomenos

Complete Question

The complete question is shown on the uploaded image

Answer:

The nuclei experience a force that will move it to the right of the conductor rod while the electrons experience a force that will move it to the left side of the conductor rod.

Explanation:

The force that act on the charges(both the positive and the negative charge ) is Mathematically expressed as

F = qE => E = F/q

where F is the force, q is the charge and E is the electric field

we can see that the force is directly proportional to the electric field,so an increase in the electric field would increase the force.

we can also see that the electric field is given as force per unit charge and generally the direction of this field is taken to be the direction of the force it would exert on a positive test charge

Now from the question we are being told that the external electric field is the direction of the positive x axis

Hence this field would drive the positive charge i.e the nuclei to the right.

In order to further explain let consider this

Generally the electric field is always radially outward originating from a positive point charge and radially in toward a negative point charge.

what this means for this question, is that the positive point charge is on the left side of the electric field while the negative point charge is at the right side of the field.

According to Coulomb's law which states that unlike term attract while like terms repel, it means that the electron would move to the left of the conductor rod while the nuclei would move to the right side of the conductor rod.