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sdas [7]
3 years ago
11

You walk with a velocity of 2 m/s north. You see a man approaching you, and from your frame of reference he has a speed of 3 m/s

to the south. What is the velocity of the man from the frame of reference of a stationary observer? (2 points)
Physics
1 answer:
kupik [55]3 years ago
5 0
The answer to this question would be: 1m/s

When you are walking to the north with 2m/s velocity, the stationary object(velocity=0m/s) will look like moving south at 2m/s velocity. That happens because the relative distance between you and the object is reduced by 2m/s in both conditions. In this question, the man seems like have 3m/s velocity. The real velocity should be:
3m/s - 2m/s = 1m/s
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Answer:

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Explanation:

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Now by putting the value

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We know that mass of electron

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a= Acceleration of electron

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a=6.2\times 10^{19} m/s^2

S=ut+\dfrac{1}{2}at^2

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20\times 10^{-9}=\dfrac{1}{2}\times 6.2\times 10^{19} t^2

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Exercise 1;

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