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sdas [7]
4 years ago
11

You walk with a velocity of 2 m/s north. You see a man approaching you, and from your frame of reference he has a speed of 3 m/s

to the south. What is the velocity of the man from the frame of reference of a stationary observer? (2 points)
Physics
1 answer:
kupik [55]4 years ago
5 0
The answer to this question would be: 1m/s

When you are walking to the north with 2m/s velocity, the stationary object(velocity=0m/s) will look like moving south at 2m/s velocity. That happens because the relative distance between you and the object is reduced by 2m/s in both conditions. In this question, the man seems like have 3m/s velocity. The real velocity should be:
3m/s - 2m/s = 1m/s
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If a small motor does 520 J of work to move a toy car 260 m in 3.0 seconds, how much power is being applied by the motor?
Lubov Fominskaja [6]

Answer:

P = 173.33 [W]

Explanation:

Power is defined as the amount of work done over a given time.

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t = time = 3 [s]

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Therefore by working relationship over time we can calculate the power.

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4 0
3 years ago
Describe the motion of an object:
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Answer:

A. Here object is moving with increasing velocity

B. Here the object is moving with decreasing velocity that is it is decelerating

C. Here the initial and final velocity are the same so the object moves at constant velocity

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4 years ago
To calculate the heat needed to boil a pot of water at 100 c, what do you need to know?
Setler [38]

<u>To calculate the energy which needed to any heating, we need to know:</u>

  1. <u>The mass</u> of the heated material (kg), as the water in your problem
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Then, using the relation of heat energy

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7 0
3 years ago
A 1,000 kg car is travelling at 6.5 m/s to the North. A 3,500 kg truck is travelling South at the same velocity. What is the tot
Molodets [167]

Answer:

16250 kgm/s due south

Explanation:

Applying,

M = mv................. Equation 1

Where M = momentum, m = mass, v = velocity.

From the car,

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Substitute these values into equation 1

M = 1000(6.5)

M = 6500 kgm/s

For the truck,

Given: m = 3500 kg, v = 6.5 m/s

Substitute these values into equation 1

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From the question,

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Total momentum of the two vehicles = -16250 kgm/s

Hence the total momentum of the two vehicles is 16250 kgm/s due south

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3 years ago
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