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3 years ago

9

A golfer takes two putts to get his ball into the hole he is on green. The first putt displaces the ball 4.5m east, and the seco

nd 8.27 m south. What displacement would have been needed to get the ball into the hole on the first putt.

1 answer:

LenaWriter [7]3 years ago

8 0

I think its the one going it at 4.5m

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If a body having mass 40kg started moving initially with rest and it takes a velocity of 20m/sec in time 4 seconds. Find the val

baherus [9]

${\mathfrak{\underline{\purple{\:\:\: Given:-\:\:\:}}}} \\ \\$

$\:\:\:\:\bullet\:\:\:\sf{Mass \ of \ the \ body \ (m) = 40 \ kg}$

$\:\:\:\:\bullet\:\:\:\sf{Final \ velocity \ of \ the \ body \ (v) = 20 \ m/s}$

$\:\:\:\:\bullet\:\:\:\sf{Initial \ velocity \ of \ the \ body \ (u) = 0}$

$\\$

${\mathfrak{\underline{\purple{\:\:\:To \:Find:-\:\:\:}}}} \\ \\$

$\:\:\:\:\bullet\:\:\:\sf{Force \ exerted \ by \ the \ body \ ( F)}$

$\\$

${\mathfrak{\underline{\purple{\:\:\: Solution:-\:\:\:}}}} \\ \\$

☯ <u>Using 1st equation of motion </u>

$\\$

$\dashrightarrow\:\: \sf{v = u + at}$

$\\$

$\dashrightarrow\:\: \sf{20 = 0 + a(4)}$

$\\$

$\dashrightarrow\:\: \sf{20 = 4a}$

$\\$

$\dashrightarrow\:\: \sf{\dfrac{\cancel{20}}{\cancel{4}} = a}$

$\\$

$\dashrightarrow\:\: \sf{a = 5}$

$\\$

☯ <u>Now, Finding the force exerted </u>

$\\$

$\dashrightarrow\:\: \sf{F = ma}$

$\\$

$\dashrightarrow\:\: \sf{F = 40 \times 5}$

$\\$

$\dashrightarrow\:\: \sf{F = 200 \ N}$

$\\$

☯ <u>Hence</u>, $\\$

$\:\:\:\:\star\:\:\:\sf{The \ force \ exerted \ by \ the \ body \ is \ 200N}$

8 0

2 years ago

What sound signal tells a river lock attendant that you wish to go through the lock?

Hoochie [10]

In order to tell a river lock attendant that you wish to go through the lock, you should <span>sound one prolonged blast followed by one short blast.

You should wait about 400 feet away from the lock and wait for the flashing light signal that allows you to enter.
Also note that </span><span>commercial traffic always have the first priority in entering the locks.</span>

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3 years ago

3. A 900N mountain climber scales a

Umnica [9.8K]

Answer:

<h2>135,000 J</h2>

Explanation:

The work done by an object can be found by using the formula

workdone = force × distance

From the question we have

workdone = 900 × 150

We have the final answer as

<h3>135,000 J</h3>

Hope this helps you

4 0

2 years ago

The gravitational acceleration is 9.81 m/s2 here on Earth at sea level. What is the gravitational acceleration at a height of 35

azamat

To solve this problem it is necessary to apply the definition of severity of Newtonian laws in which it is specified that gravity is defined by

$g= \frac{GM}{R^2}$

Where

G= Gravitational Constant

M = Mass of Earth

R= Radius from center of the planet

According to the information we need to find the gravity 350km more than the radius of Earth, then

$g_{ss} = \frac{GM}{R+h^2}$

$g_{ss} = \frac{6.67*10^{-11}*5.972*10^{24}}{(6371*10^3+350*10^3)^2}$

$g_{ss} = 8.82m/s^2$

Therefore the gravitational acceleration at 350km is $8.82m/s^2$

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3 years ago

a wave travels at a speed of 793 m/s and has a wavelength of 2.3 meters. calculate the frequency of the wave

Savatey [412]

Answer:

344.8 Hz

Explanation:

The frequency of a wave is given by:

$f=\frac{v}{\lambda}$

where

v is the speed of the wave

$\lambda$ is its wavelength

Here we have

v = 793 m/s

$\lambda=2.3 m$

Substituting into the equation, we find

$f=\frac{793 m/s}{2.3 m}=344.8 Hz$

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2 years ago