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3 years ago

The sum of two consecutive even integers is -34 what is the smaller integers

1 answer:

3 0

Even integers are 2 apart

they are n and n+2

n+n+2=-34
2n+2=-34
minus 2 both sides
2n=-36
divide 2
n=-18
n+2=-16
de smaller is -18

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the area of a rectangular patio is represented by the expression 6x^2+13-5. the width of the patio is (3x-1) write an expression

jok3333 [9.3K]

I think you meant 6x²+13x-5 so first thing we have to do is factor it which is really quite tricky with this kind of trinomial so first take ac which is 6 times -5 so -30 now figure out factors of -30 that will add up to 13 how about 15 and -2 now that we have the factors write the equation again

6x²+15x-2x-5 split the equation in half

6x²+15x -2x-5 so out of the first equation we can pull a 3x out

3x(2x+5) and out of the second we can pull a negative 1

3x(2x+5) -1(2x+5) rewrite it

(3x-1)(2x+5) so the 3x-1 is the factor we already had so the other side is (2x+5)

HOPE THIS HELPS!!!

6 0

3 years ago

Use the correct function to find the missing angle y measurement to the

Doss [256]

Answer:

Cos;

26 degrees

Step-by-step explanation:

Recall: SOH CAH TOA

Reference angle = y°

Adjacent side = 18 in.

Hypotenuse = 20 in.

We would apply the trigonometric function CAH since we are dealing with the Adjacent side (A) and the Hypotenuse (H). Thus:

Cos y° = Adj/Hyp

Cos y° = 18/20

Cos y° = 0.9

y° = cos^{-1}(0.9)

y = 25.8419328° ≈ 26 degrees (nearest whole degree)

The answers are:

Cos and 26 degrees

4 0

3 years ago

The longer leg of a 30,-60,-90 degree triangle is 18: what is the length of the other leg

taurus [48]

Answer:

The other legs are 9 and 9√3

Step-by-step explanation:

The longer side of a 30-60-90 degree rectangle is 18.

The other legs will be

$\frac{x}{2}$

and

$\frac{x}{2} \sqrt{3}$

Where x is the longest side, which is given as 18.

Therefore one leg will be:

$\frac{18}{2} = 9$

and the other leg will be:

$\frac{18}{2} \sqrt{3} = 9 \sqrt{3}$

4 0

3 years ago

NO LINKS!! Use the method of substitution to solve the system. (If there's no solution, enter no solution). Part 11z

Roman55 [17]

Answer:

$(x,y)=\left(\; \boxed{-1,-8} \; \right)\quad \textsf{(smaller $x$-value)}$

$(x,y)=\left(\; \boxed{5,16} \; \right)\quad \textsf{(larger $x$-value)}$

Step-by-step explanation:

Given system of equations:

$\begin{cases}y=x^2-9\\y=4x-4\end{cases}$

To solve by the method of substitution, substitute the first equation into the second equation and rearrange so that the equation equals zero:

$\begin{aligned}x^2-9&=4x-4\\x^2-4x-9&=-4\\x^2-4x-5&=0\end{aligned}$