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In-s [12.5K]
3 years ago
9

Jean add 35 + 9. How can she solve using only equations to model her thinking?

Mathematics
1 answer:
Alexus [3.1K]3 years ago
8 0

Answer:

( 35+9=44)

Step-by-step explanation:

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Which expression has a positive value?<br> (-5)(-9)<br> 2-4<br> 12-1-4)<br> -3+(-7)
11111nata11111 [884]

Answer:

(-5)(-9)

Step-by-step explanation:

any negative multiplied by any negative will always equal a positive

7 0
3 years ago
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Find the exact value of sec theta if csc theta = -4/3 and the terminal side of theta lies in quadrant III
GREYUIT [131]

Answer:

-4 sqrt(7)/7

Step-by-step explanation:

csc theta = -4/3

csc theta = hypotenuse / opposite side

hypotenuse = 4  

opposite  = 3

Using the pythagorean theorem

a^2 + b^2 = c^2

3^2 + b^2 = 4^2

9+b^2 = 16

b^2 = 16-9

b^2 = 7

Taking the square root

sqrt(b^2) = sqrt(7)

b = sqrt(7)

We are in the third quadrant so only tan  and cot are positive

that means the x and y values are "negative"  so a = -3 and b = - sqrt(7)

sec theta = hypotenuse / adjacent

                = 4/ - sqrt(7)

rationalizing  

                   -4 sqrt(7)/ sqrt(7)* sqrt(7)

                = -4 sqrt(7)/7

           

3 0
3 years ago
What is the sum of 2.5 x 10^4 and 3.4 x 10^4
navik [9.2K]

5.9 x 10^4

59000

That is the answer C

3 0
3 years ago
Find the missing end point if H is the midpoint of PS. P(2,5) and H (3,4) find S (endpoint)
RUDIKE [14]

Answer:

(4,3)

Step-by-step explanation:

To find the midpoint add the end points and divide by 2

P(2,5)    S ( sx, sy)  and the midpoint is and H (3,4)

X coordinate

( 2+ sx) /2 = 3

Multiply each side by 2

2+sx = 3*2

2+sx = 6

Subtract 2

sx = 4

Y coordinate

( 5+ sy) /2 = 4

Multiply each side by 2

5+sy = 4*2

5+sy = 8

Subtract 5

sy = 3

The end point is

(4,3)

8 0
3 years ago
Read 2 more answers
A frog is climbing out of a well that is 11 feet deep. The frog can climb 3 feet per hour but then it rests for an hour, during
Dimas [21]

Answer:

It takes the frog 7 hours to get out of the well.

Step-by-step explanation:

We know that the well is 11 feet deep and the frog can climb 3 feet per hour.

Each time it climbs, it rests for an hour, and decreases its height by 1 foot.

So, if the frog reaches 3 feet in the first hour, then in the next hour it is 2 feet.

Lets calculate with the same pattern:

1st hour: 3 feet

2nd hour: 3-1=2 feet

3rd hour: 2+3=5 feet

4th hour: 5-1=4 feet

5th hour: 4 +3= 7 feet

6th hour: 7-1=6 feet

5th hour: 6+3=9 feet

6th hour: 9-1=8 feet

7th hour:  8+3= 11 feet

Therefore, it takes the frog 7 hours to get out of the well.

4 0
3 years ago
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