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bazaltina [42]
3 years ago
15

Make p the subject of the formula. 4(p-2p)=3+2

Mathematics
1 answer:
liberstina [14]3 years ago
4 0

Answer:

p=-5/4

Step-by-step explanation:

expand brackets

4p-8p=3+2

simplify

-4p=5

divide by -4

p=-5/4

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Suppose you have 62 feet of fencing to go around a rectangular flower garden. You want
koban [17]

Answer:

Answer is 9 feet = 9 fe 2t

w= 9fe 2t

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Given r(x) = 11/ (x - 42)
julsineya [31]

For a given function f(x) we define the domain restrictions as values of x that we can not use in our function. Also, for a function f(x) we define the inverse g(x) as a function such that:

g(f(x)) = x = f(g(x))

<u>The restriction is:</u>

x ≠ 4

<u>The inverse is:</u>

y = 4 + \sqrt{\frac{11}{x} }

Here our function is:

f(x) = \frac{11}{(x - 4)^2}

We know that we can not divide by zero, so the only restriction in this function will be the one that makes the denominator equal to zero.

(x - 4)^2 = 0

x - 4 = 0

x = 4

So the only value of x that we need to remove from the domain is x = 4.

To find the inverse we try with the general form:

g(x) = a + \sqrt{\frac{b}{x} }

Evaluating this in our function we get:

g(f(x)) = a + \sqrt{\frac{b}{f(x)} }  = a + \sqrt{\frac{b*(x - 4)^2}{11 }}\\\\g(f(x)) = a + \sqrt{\frac{b}{11 }}*(x - 4)

Remember that the thing above must be equal to x, so we get:

g(f(x)) = a + \sqrt{\frac{b}{11 }}*(x - 4) = x\\\\{\frac{b}{11 }} = 1\\{\frac{b}{11 }}*4 - a = 0

From the two above equations we find:

b = 11

a = 4

Thus the inverse equation is:

y = 4 + \sqrt{\frac{11}{x} }

If you want to learn more, you can read:

brainly.com/question/10300045

3 0
2 years ago
25 POINTS PLEASE HELP ME!! Sam conjectures that for x ≤ - 2, it is true that x^5 + 7 &gt; x^3. Is Sam’s conjecture correct? Why
CaHeK987 [17]

The true statement about Sam’s conjecture is that the conjecture is not correct

<h3>How to determine if Sam’s conjecture is correct or not?</h3>

Sam’s conjecture is given as:

For x ≤ - 2

It is true that x^5 + 7 > x^3.

The inequality x ≤ - 2 means that the highest value of x is -2

Assume the value of x is -2, then we have:

(-2)^5 + 7 > (-2)^3

Evaluate the exponents

-32 + 7 > -8

Evaluate the sum

-25 > -8

The above inequality is false because -8 is greater than -25 i.e. -8 > -25 or -25 < -8

Hence, the true statement about Sam’s conjecture is that the conjecture is not correct

Read more about conjectures at

brainly.com/question/20409479

#SPJ1

5 0
2 years ago
Fill in Sin, Cos, and tan ratio for angle x. <br> Sin X = 4/5 (28/35 simplified)
Fantom [35]

Answer:

Given: \sin(x) = (4/5).

Assuming that 0 < x < 90^{\circ}, \cos(x) = (3/5) while \tan(x) = (4/3).

Step-by-step explanation:

By the Pythagorean identity \sin^{2}(x) + \cos^{2}(x) = 1.

Assuming that 0 < x < 90^{\circ}, 0 < \cos(x) < 1.

Rearrange the Pythagorean identity to find an expression for \cos(x).

\cos^{2}(x) = 1 - \sin^{2}(x).

Given that 0 < \cos(x) < 1:

\begin{aligned} &\cos(x) \\ &= \sqrt{1 - \sin^{2}(x)} \\ &= \sqrt{1 - \left(\frac{4}{5}\right)^{2}} \\ &= \sqrt{1 - \frac{16}{25}} \\ &= \frac{3}{5}\end{aligned}.

Hence, \tan(x) would be:

\begin{aligned}& \tan(x) \\ &= \frac{\sin(x)}{\cos(x)} \\ &= \frac{(4/5)}{(3/5)} \\ &= \frac{4}{3}\end{aligned}.

7 0
2 years ago
1-cos^2 A / sec^2 A - tan^2 A
tiny-mole [99]
I hope this helps you



✔cos^2A+sin^2A=1


✔1-cos^2A=sin^2A

✔cos2A=cos^2A-sin^2A

✔sin2A=2.sinA.cosA


secA=1/cosA


tgA=sinA/cosA


sin^2A/1/cos^2A-sin^2A/cos^2A


sin^2A.cos^2A/cos2A

2.sin^2A.cos^2A/cos2A


sin2A.2.sin2A/cos2A


tg2A.2.sin2A


6 0
3 years ago
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