Fill in the bubble for the correct answer choice.

Please just help me im literally crying I dont want links to your math websites our teacher didnt teach us like half this stuff

8090 [49]

Answer:

Okay?

Step-by-step explanation:

I think m a week or 2 late

8 0

2 years ago

Who can help me to solve these questions please?

ankoles [38]

Using the given information, length of QR = 16.6 cm

The area of the trapezium is 304.5 cm²

<h3>Calculating area of a trapezium</h3>

From the question we are to calculate the length of QR and the area of trapezium PQRS

In the given diagram,

Let the midpoint of PS be T

Then, we can write that

|OP|² = |OT|² + |PT|² (<em>Pythagorean theorem</em>)

|OP| = radius = 13 cm

|PT| = 1/2 × PS = 1/2 × 24 cm = 12 cm

∴ 13² = |OT|² + 12²

169 = |OT|² + 144

|OT|² = 169 -144

|OT|² = 25

|OT| = √25

|OT| = 5 cm

Also, let the midpoint of QR be U

Then, we can write that

|OQ|² = |OU|² + |QU|² (<em>Pythagorean theorem</em>)

|OQ| = radius = 13 cm

From the given information,

The distance of QR from O is twice the distance of PS from O

∴ |OU| = 2 × |OT|= 2 × 5 cm = 10cm

Thus,

13² = ||² + 12²

169 = 10² + |QU|²

|QU|² = 169 -100

|QU|² = 69

|QU| = √69

|QU| = 8.3 cm

Now,

Length of QR = 2 × |QU| = 2 × 8.3 cm

Length of QR = 16.6 cm

b)

Area of the trapezium = 1/2(|QR| + |PS|) × |TU|

Area of the trapezium = 1/2(16.6 + 24) × 15

NOTE: |TU| = |OT| + |OU|

Area of the trapezium = 1/2(40.6) × 15

Area of the trapezium = 20.3 × 15

Area of the trapezium = 304.5 cm²

Hence, the area of the trapezium is 304.5 cm²

Learn more on Calculating area of trapezium here: brainly.com/question/3435635

#SPJ1

7 0

2 years ago

A rectangular piece of metal is 25 in longer than it is wide. Squares with sides 5 in long are cut from the four corners and the

Licemer1 [7]

Answer:

The original length was 41 inches and the original width was 16 inches

Step-by-step explanation:

Let

x ----> the original length of the piece of metal

y ----> the original width of the piece of metal

we know that

When squares with sides 5 in long are cut from the four corners and the flaps are folded upward to form an open box

The dimensions of the box are

$L=(x-10)\ in\\W=(y-10)\ in\\H=5\ in$

The volume of the box is equal to

$V=(x-10)(y-10)5$

$V=930\ in^3$

so

$930=(x-10)(y-10)5$

simplify

$186=(x-10)(y-10)$ -----> equation A

Remember that

The piece of metal is 25 in longer than it is wide

so

$x=y+25$ ----> equation B

substitute equation B in equation A

$186=(y+25-10)(y-10)$

solve for y

$186=(y+15)(y-10)\\186=y^2-10y+15y-150\\y^2+5y-336=0$

Solve the quadratic equation by graphing

using a graphing tool

The solution is y=16

see the attached figure

Find the value of x

$x=16+25=41$

therefore

The original length was 41 inches and the original width was 16 inches

3 0

3 years ago

I'm having a little bit of trouble figuring out the formula to solve this problem.

goldfiish [28.3K]

Answer:Red price hast he least least cost per gram of apple.

Step-by-step explanation:

1) considering Royal Gala, 75 gram apple cost $0.41

The cost per gram is 0.41/75 = $0.0055

2) considering Honey crisp, 93 gram apple cost $0.82

The cost per gram is 0.82/93 = $0.0088

3) considering Red Prince, 81 gram apple cost $0.36

The cost per gram is 0.36/81 = $0.0044

Since $0.0044 per gram is the lowest of the three, then the type of apple with the least cost per gram is Red prince.

6 0

3 years ago

Whats the difference between linear equations and quadratic equation

SIZIF [17.4K]

Answer:

Step-by-step explanation:

A linear equation in two variables doesn't involve any power higher than one for either variable. It has the general form Ax + By + C = 0, where A, B and C are constants. ... A quadratic equation, on the other hand, involves one of the variables raised to the second power. It has the general form y = ax2 + bx + c

4 0

3 years ago