Answer:
C −2a^3+9a^2+45a+6ab^2+18b^2
Step-by-step explanation:
(a+3) ( −2a^2+15a+6b^2)
Distribute the a to the large term in parentheses and the 3 to the large term in parentheses
a ( −2a^2+15a+6b^2)+3 ( −2a^2+15a+6b^2)
−2a^3+15a^2+6ab^2 −6a^2+45a+18b^2
Combine like terms
−2a^3+15a^2−6a^2+6ab^2 +45a+18b^2
-2 a^3 + 9 a^2 + 6 a b^2 + 45 a + 18 b^2
6x-18
you pretty much h just multiply both the first part of the parentheses by the number outside, then the second :)
Answer: This is what I could figure out
Step-by-step explanation:
Answer:
hope this helps (look in the picture)
Step-by-step explanation:
Postulate, because we just assume that it is a true fact.