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e-lub [12.9K]
3 years ago
7

14. A rectangle has a width described by the expression (x2 + 2x – 15)/x and a length described by the expression

Mathematics
1 answer:
tensa zangetsu [6.8K]3 years ago
8 0

Answer:

The answer to your question is Perimeter = [4x³ + 14x² + 50x - 150] / x(5 + x)

Step-by-step explanation:

Data

Width = (x² + 2x - 15)/x

Length = (3x² + 4x)/ (5 + x)

Process

1.- Write the formula for the perimeter of a rectangle

Perimeter = 2W + 2L

2.- Substitution

Perimeter = 2(x² + 2x - 15)/x + 2(3x² + 4x)/(5 + x)

3.- Simplification

Perimeter = (2x² + 4x - 30)/x + (6x² + 8x)/(5 + x)

4.- Sum the fractions

Least common factor = x(5 + x)

Perimeter = [(2x² + 4x - 30)(5 + x) + (x(6x² + 8x)] / x(5 + x)

-Simplification

Perimeter = [10x² + 20x - 150 - 2x³ - 4x² + 30x + 6x³ + 8x²] / x(5 + x)

Perimeter = [4x³ + 14x² + 50x - 150] / x(5 + x)

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Q and r are independent events. if p(q) = 1/4 and p(r)=1/5, find p(q and r)
klasskru [66]

Answer:

(b) \frac{7}{30}

Step-by-step explanation:

When two p and q events are independent then, by definition:

P (p and q) = P (p) * P (q)

Then, if q and r are independent events then:

P(q and r) = P(q)*P(r) = 1/4*1/5

P(q and r) = 1/20

P(q and r) = 0.05


In the question that is shown in the attached image, we have two separate urns. The amount of white balls that we take in the first urn does not affect the amount of white balls we could get in the second urn. This means that both events are independent.


In the first ballot box there are 9 balls, 3 white and 6 yellow.

Then the probability of obtaining a white ball from the first ballot box is:

P (W_{u_1}) = \frac{3}{9} = \frac{1}{3}

In the second ballot box there are 10 balls, 7 white and 3 yellow.

Then the probability of obtaining a white ball from the second ballot box is:

P (W_{u_2}) = \frac{7}{10}

We want to know the probability of obtaining a white ball in both urns. This is: P(W_{u_1} and W_{u_2})  

As the events are independent:

P(W_{u_1} and W_{u_2})  = P (W_{u_1}) * P (W_{u_2})

P(W_{u_1} and W_{u_2})  = \frac{1}{3}* \frac{7}{10}

P(W_{u_1} and W_{u_2})  = \frac{7}{30}

Finally the correct option is (b) \frac{7}{30}

3 0
3 years ago
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