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Tpy6a [65]
3 years ago
12

A normal distribution has a mean of µ = 100 with σ = 20. if one score is randomly selected from this distribution, what is the p

robability that the score will be less than x = 84?​
Mathematics
1 answer:
avanturin [10]3 years ago
8 0

Given: Mean of Normal distribution μ = 100, standard deviation σ =20

We have to find the probability that the score will be less than X=84

P(X < 84)

The z-score for x=84 is

Z = \frac{x-mean}{standard deviation}

Z = \frac{84-100}{20}

Z = -0.8

We have to find probability that Z < -0.8

Using Z score table to find the probability below z=-0.8 we get

P(Z < -0.8) = 0.2119

Hence the probability that the score will be less than x = 84 is 0.2119

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dedylja [7]

Answer:

g(x)= x^2+10x + 24.

Step-by-step explanation:

g(x) = (x + 5)^2 −1

= x^2 + 5x + 5x + 25 - 1

= x^2 + 10x + 24

g(x)= x^2+10x + 24 is your answer.

Hope this helps!

4 0
3 years ago
Read 2 more answers
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Pie

Answer:

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Step-by-step explanation:

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So (A+B)(A+B)=A.A+B.A+A.B+B.B

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