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DaniilM [7]
3 years ago
5

Is sqrt(25a^2/4) the same as sqrt(25a^2)/sqrt(4)?

Mathematics
2 answers:
Evgesh-ka [11]3 years ago
6 0
LHS\\ \\ =\sqrt { \frac { 25{ a }^{ 2 } }{ 4 }  } \\ \\ ={ \left( \frac { 25{ a }^{ 2 } }{ 4 }  \right)  }^{ \frac { 1 }{ 2 }  }

\\ \\ =\frac { { \left( 25{ a }^{ 2 } \right)  }^{ \frac { 1 }{ 2 }  } }{ { 4 }^{ \frac { 1 }{ 2 }  } } \\ \\ =\frac { \sqrt { 25{ a }^{ 2 } }  }{ \sqrt { 4 }  } \\ \\ =RHS
xenn [34]3 years ago
5 0
Yes, because \sqrt{\dfrac{a}{b}}=\dfrac{\sqrt a}{\sqrt b}
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Learn this...it helps

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What is the slope intercept form of a line that passes through (-1,-5) and (4,-2)
Hatshy [7]

\bf (\stackrel{x_1}{-1}~,~\stackrel{y_1}{-5})\qquad (\stackrel{x_2}{4}~,~\stackrel{y_2}{-2}) \\\\\\ \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{-2}-\stackrel{y1}{(-5)}}}{\underset{run} {\underset{x_2}{4}-\underset{x_1}{(-1)}}}\implies \cfrac{-2+5}{4+1}\implies \cfrac{3}{5}

3 0
3 years ago
R + 3 1/2 = -4 2/3
alexandr402 [8]

Answer:

R = -8 1/6

Step-by-step explanation:

We'll solve the given equation for R.

Subtract 3 1/2 from both sides of the equation, to isolate R:

           R +  3 1/2  -  3 1/2 = -4 2/3  - 3 1/2, or

            R = -4 2/3 - 3 1/2

The LCD here is 6, which is the product of 3 and 2.  Converting the fractions to denominator 6, we get:

              R = -4 4/6 - 3 3/6, or

               R = -7 - 7/6, or R = -7 - 1 1/6, or -8 1/6

3 0
3 years ago
Is the answer<br> A.-6y=- 12<br> B.-6y=12 <br> C. -2y=-12<br> D.2y=12
polet [3.4K]

Answer:

The answer would not be A. It is B

Step-by-step explanation:

Because you are subtracting the equations, on the right side of the equal sign, you are subtracting -5 from 7. This is 7-(-5), which is equal to 7+5=12, not -12.

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