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DaniilM [7]
3 years ago
5

Is sqrt(25a^2/4) the same as sqrt(25a^2)/sqrt(4)?

Mathematics
2 answers:
Evgesh-ka [11]3 years ago
6 0
LHS\\ \\ =\sqrt { \frac { 25{ a }^{ 2 } }{ 4 }  } \\ \\ ={ \left( \frac { 25{ a }^{ 2 } }{ 4 }  \right)  }^{ \frac { 1 }{ 2 }  }

\\ \\ =\frac { { \left( 25{ a }^{ 2 } \right)  }^{ \frac { 1 }{ 2 }  } }{ { 4 }^{ \frac { 1 }{ 2 }  } } \\ \\ =\frac { \sqrt { 25{ a }^{ 2 } }  }{ \sqrt { 4 }  } \\ \\ =RHS
xenn [34]3 years ago
5 0
Yes, because \sqrt{\dfrac{a}{b}}=\dfrac{\sqrt a}{\sqrt b}
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grandymaker [24]

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Common ratio is:

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Rounding off to nearest hundredth

$1757.49

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Leo's balance after 9 months will be: $1757.49

Keywords: Geometric sequence, balance

Learn more about geometric sequence at:

  • brainly.com/question/10772025
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#LearnwithBrainly

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