You have 100 yards of fencing available to create an enclosure for farm animals. As the

1 answer:

3 0

1. area of a pentagon when 1 side is x is $\frac{x^2}{4}\sqrt{5(5+2\sqrt{5})}$
so if perimiter is 100 then one side is 100/5 or 20
area will be $\frac{20^2}{4}\sqrt{5(5+2\sqrt{5})}$ ≈688.2 square yards

2. area of a hexagon when 1 side is length x is $\frac{3x^2\sqrt{3}}{2}$
so if permiter is 100 then length of one side is 100/6 or about 16.666666666666
the area will be $\frac{3(16.6666666)^2\sqrt{3}}{2}$ ≈721.7 square yards

3. area of a regular octagon with side lenghts x is $2(1+\sqrt{2})x^2$
so if 8 sides then side length of each is 100/8 or 12.5
area will be $2(1+\sqrt{2})12.5^2$ ≈754.4 square yards

octagon wil have most space
you can tell because the more sides it has, the more it gets to a circle and the more area it encloses with a given perimiter

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A support wire is attached to the top of a tower that is 65 feet tall as shown. If the wire makes an angle of 34 degree with the

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Answer:
length of wire = 116 ft

Explanation:
The attached image shows a diagram on the scenario given.

Now, we can note that the string forms a right-angled triangle with the tower and the ground. This means that special trig functions can be applied.
These functions are as follows:
sin θ = opposite / hypotenuse
cos θ = adjacent / hypotenuse
tan θ = opposite / adjacent

Now, from the given, we can find that:
θ = 34°
opposite is the tower = 65 ft
hypotenuse is the string length that we want to find

Substitute with the givens in the sin function to get the length of string as follows:
sin (34) = 65 / string
string = 65 / sin(34)
string = 116.2 which is approximately 116 ft

Hope this helps :)