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zvonat [6]
4 years ago
10

What is the 23rd term from these sequences   5,6,7,8,9

Mathematics
2 answers:
Leokris [45]4 years ago
8 0
This is the formula you should use. term one + (term you want - 1)common difference
27 is the first one, 29 is the second one
FromTheMoon [43]4 years ago
4 0
The answer is 31. :)
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hram777 [196]
Answer: A.)

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3 years ago
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Help me plss plss I really need help I have a f
Colt1911 [192]

Answer:

A. 5 1/2 and D. 11/2

Step-by-step explanation:

Make improper fraction

8*1+3=11/8

Solve by multiplying:

4*11/8

44/8

Simplified is 11/2

We can turn it back into a mixed number

2*5+1=11 so 5 1/2

6 0
3 years ago
Can anyone help I am doing really mad in math
Vadim26 [7]

For this problem, we are going to have to use our order of operations, which is: Parentheses, Exponents, Multiplication and Division, and Addition and Subtraction (often abbreviated PEMDAS).


First, let's see if there are any parentheses. There is one set of parentheses which we will have to remove. To do this, we will simply multiply the -4 by the 6, given us a value of -24 to take the place of the -4(6). Now our problem is:

\dfrac{12^2 - 24 + 1}{11^2}


Next, we will check for exponents. There are exponents, so we will need to take care of those. 12^2 is equal to 144, and 11^2 is equal to 121. We can now substitute these values into the original expression to get:

\dfrac{144 - 24 + 1}{121}


Now, we will check for any multiplication or division. Besides the entire expression (which is a fraction), there is none, so we will move on to the next step: Addition and Subtraction. You can see there is addition and subtraction in the numerator. 144 - 24 is equal to 120, and 120 + 1 is equal to 121. Our problem is now:

\dfrac{121}{121} = \boxed{1}


Our answer is 1.

8 0
4 years ago
Abbotsford
weqwewe [10]

Answer:

a^2 + b^2 = c^2

Step-by-step explanation:

The distance from Abbotsford to Kelso is 17 km. That is your "a" value. The distance from Abbotsford to Hawick is 15 km.

7 0
3 years ago
Read 2 more answers
The product of three consecutive even integers is 39,168.
Ainat [17]

Answer:

Step-by-step explanation:

hello :

let :  three consecutive even integers : 2n  , 2n+2  , 2n+4

a) the polynomial is : 2n(2n+2)(2n+4) = 39168

but : 39168=2^8 ×3²×17 =2^5×2×17×9×2^2 because : 2^8=2^5×2×2^2

39168=32×34×36  because : 2^5=32  and  2×17 =34 and 9×2^2 =36

conclusion : three consecutive even integers are : 32 ,34 ,36

8 0
3 years ago
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