Point X lies on a horizontal line. We can intuitively say that the slope of the graph at point X is 0, therefore the acceleration at point X is 0m/s²
Point Y lies on a downward slanting line. To calculate the slope of that line, let's apply this equation:
m = (y₂-y₁)/(x₂-x₁)
m = slope, (x₁, y₁) and (x₂, y₂) correspond to the coordinates of the line's endpoints.
Given values:
(x₁, y₁) = (7, 5)
(x₂, y₂) = (12, 0)
Plug in and solve for m:
m = (0 - 5)/(12 - 7)
m = -1
The acceleration at point Y is -1m/s²
Choice A
Answer:
18.6012339739 A
Explanation:
= Vacuum permeability = 
L = Length of wire = 55 cm
N = Number of turns = 4000
I = Current
Magnetic field is given by
The current necessary to produce this field is 18.6012339739 A
The EMF generated by Faraday's law of induction due to relative movement of a circuit and a magnetic field is the phenomenon underlying electrical generators. When a permanent magnet is moved relative to a conductor, or vice versa, an electromotive force is created.
Answer:
B Eight light-minutes
Explanation:
In the case when the distance separated earth and the sun so here we orbit the sun for a 150 million km distance and the light moves would be 300,000 kilometers per second
Now divide this
= 150 million ÷ 300,000 kilometers per second
= 500 seconds
This 500 seconds represent 8 minutes and 20 seconds
Hence, option B is correct
Answer:a) The linear speed of the rotating merry-go-round is 1.884 m/s.
b) The acceleration of the rotating merry-go-round device is 
.
Explanation:
a) linear speed of the device:
Distance =
Child seated 1.2 meters from the center, which means that radius ,r = 1.2 meters
Time taken to complete one revolution = 4.0 seconds
The linear speed of the rotating merry-go-round is 1.884 m/s.
b) Acceleration
Linear velocity ,v = 1.884 m/s
The acceleration of the rotating merry-go-round device is .
