By using Lami's theorem formula, the tension in the supporting wires is 48.6 Newtons
TENSION
- Tension is also a force having Newton as S.I unit.
- The tension in the wire will be the same.
This question can be solved by using either vector diagram or by using Lami's theorem.
The sum of two given angles = 42 + 42 = 84 degrees
The third angle = 180 - 84 = 96 degrees.
Below is the Lami's theorem formula
Where
= 42 + 90 = 132 degrees
Y = 96 degrees
W = 65 N
By using the formula, we have
T/sin 132 = 65/sin96
Cross multiply
T = 0.743 x 65.57
T = 48.56 N
Therefore, the tension in the supporting wires is 48.6 Newtons approximately.
Learn more about Tension here: brainly.com/question/24994188
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Answer:
The answer to your question is Equation vf = gt; vf = 29.6 m/s
Explanation:
Data
gravity = 3.7 m/s²
vf = ?
time = t = 8 s
Formula
vf = vo + gt
Initial speed = 0 m/s
To solve this problem we can use the equations of free fall and just substitute the data.
- Substitution
vf = 0 + (3.7)(8)
- Simplification
vf = 29.6 m/s
Answer:
(a) v = 65.35 m/s
(b) ac = 82.16 m/s²
Explanation:
Kinematic of the blades of the wind turbine
The blades of the wind turbine describe circular motion and the formulas that apply to this movement are as follows:
v = ω * R Formula (1)
Where:
v : tangential velocity (m/s)
ω : angular velocity (rad/s)
R : radius of the particle path (m)
The velocity vector is tangent at each point to the trajectory and its direction is that of movement. This implies that the movement has centripetal acceleration (ac):
ac = ω²* R Formula (1)
ac : centripetal acceleration (m/s²)
Data:
ω= 12 rpm = 12 rev/min
1 rev = 2π rad
1 min = 60 s
ω= 12 rev/min = 12 (2π rad)/(60 s)
ω = 1.257 rad/s
R = 52 m
(a)Tangential velocity at the tip of a blade (v)
We apply the formula (1)
v = ω* R
v = ( 1.257)* (52) = 65.35 m/s
(a) Centripetal acceleration at the tip of a blade (ac)
We apply the formula (2)
ac = ω²*R
ac = ( 1.257)²* (52) = 82.16 m/s²
