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VashaNatasha [74]
3 years ago
5

What relationship between the mass of each other and its motion after the collision do you observe? How do Newtons laws help exp

lain your observations?
remember that the action and reaction forces are equal in any collision if the action and reaction forces are equal then why do bumper cars that are of different masses react differently
Physics
1 answer:
Leni [432]3 years ago
8 0

Answer:

If the weight and forces are the same, it will result in a balance, i they are different, it will result in an overload in the lower force/mass object, reflecting it to the opposite direction with higher speed.

Explanation:

You might be interested in
A rigid tank whose volume is unknown is divided into two parts by a partition. One side of the tank contains an ideal gas at 927
Marianna [84]

Answer:

The final temperature will be 3600 K.

Explanation:

Side 1

T=927°C

T=1200 K

Lets take volume of one side is V then the volume of other side will be 2V. The final volume of system will become 3 V.

The system is closed so the mass of system will remain constant .

We know that for ideal gas  P V = m R T

The final pressure is same as initial pressure so we can say that

\dfrac{T_i}{V_i}=\dfrac{T_f}{V_f}

\dfrac{1200}{V}=\dfrac{T_f}{2V+V}

T_f=3600\ K

So the final temperature will be 3600 K.

4 0
3 years ago
What frequency must a sound wave have in air to have the same wavelength as a 750 Hz sound wave in a platinum bar? Vair = 340 m/
amm1812

Answer:

f = 91.1 Hz

Explanation:

As we know that it is given here that wavelength of sound in platinum is same as the wavelength of sound in air

so we can use the formula of wavelength in two mediums

\frac{speed}{frequency} = \frac{speed}{frequency}

now it is given that

v_{air} = 340 m/s

v_{pt} = 2800 m/s

frequency of sound in platinum is 750 Hz

now frequency of sound in air = f

now from above formula

\frac{340}{f} = \frac{2800}{750}

f = 91.1 Hz

7 0
3 years ago
If only one external force acts on a particle, does it necessarily change the particle's kinetic energy and velocity? (select al
ivann1987 [24]
It's necessary to change the particles kinetic and velocity to open external and eternal.
7 0
4 years ago
8.)The potential energy of a 40-kg cannonball is 14000 J. How high was the cannon ball to have this much potential energy?
Delvig [45]

Hey! I empathize with you, as I just started the energy unit in physics as well!

Alright, lets list what we know, and which equation(s) we need.

PE = Gravitational Potential Energy

PEg = mgh

m = mass

g = gravity (9.8 m/s^2)

h = height

Guess what?

We need to find the height!

Lets make this more organized:

Known:

m = 40 kg

PE = 14000

g = 9.8 m/s^2

Unknown:

h = ?

================================

Now, if we take a look at the equation PEg = mgh, you will see that we have everything besides the height! So lets solve for the height by substituting in for the variables we know:

14000 J = 40 kg * (9.8 m/s^2) * h

40 * 9.8 = 392  

14000 J = 392 * h

14000/392 = h

35.71 m = h

There we go! If you simply list what you know and don't know, you will find the equation you need to solve the problem.

Have a great day and good luck!

7 0
3 years ago
Com que rapidez estará sendo feito trabalho elétrico num resistor de 10 ohms, percorrido por uma corrente elétrica de 5 A? Qual
34kurt

Poder = (resistencia) x (corrente)²

Poder = (10 ohms) x (5 A)²

<em>Poder = 250 watts </em>(250 Joule por segundo)

2 horas = 7,200 segundos

Energia = (250 joule/seg) x (7,200 seg)

<em>Energia = 1,800,000 Joules</em>

7 0
3 years ago
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