Answer
given,
mass of satellite = 545 Kg
R = 6.4 x 10⁶ m
H = 2 x 6.4 x 10⁶ m
Mass of earth = 5.972 x 10²⁴ Kg
height above earth is equal to earth's mean radius
a) satellite's orbital velocity
centripetal force acting on satellite =
gravitational force =
equating both the above equation
v = 5578.5 m/s
b)
T = 14416.92 s
T = 4 hr
c) gravitational force acting
F = 5202 N
Answer:
0.249
Explanation:
Perihelion = 4.43 x 10^9 km
Aphelion = 7.37 x 10^9 km
Let e be the eccentricity and a be the length of semi major axis.
The relation between the semi major axis, perihelion and aphelion s given by
Semi major axis = half of sum of perihelion and aphelion
a = 5.9 x 10^9 km
The relation between the perihelion, semi major axis and the eccentricity is given by
Perihelion = a (1 - e)
4.43 x 10^9 = 5.9 x 10^9 (1 - e)
0.751 = 1 - e
e = 0.249