Answer:
W = 112.58 N-unit
Explanation:
Given:
- Force F = 10 N
- Angle Q of force with x axis: 30 degrees
- distance to be moved d = 13 units along + x axis
Find:
Work Done by the force F:
Solution:
The work by force in positive x direction can only be done if the both the direction of distance traveled and direction of force are parallel vectors. Hence we compute the component of Force F in x direction F_x:
F_x = F*cos(Q)
F_x = 10*cos(30)
F_x = 8.66 N
Hence,
Work Done by force
W = F_x * d
W = 8.66 * 13
W = 112.58 N-unit
The rectilinear motion is given as:
s = s0 + v0 t + (1/2) a t^2
We can see that the variables stand for:
s = final distance
s0 = initial distance
v0 = initial velocity
t = time
a = acceleration
<span>We can see that all these variable are always constant
EXCEPT acceleration. The rectilinear motion can only be applied if and only if
acceleration is CONSTANT.</span>
Answer: 3976N
Explanation:
Using the formula for calculating gravitational force between two masses, we have
F = GMm/r^2
Where G is the gravitational constant
M and m are the masses
r is the distance between the masses
F= 6.673 × 10-¹¹ × 5.98 × 10²⁴ × 63.5/ (6.37 × 10^6)^2
F= 2.533×10^16/6.37×10^12
F= 0.3976×10⁴N
F= 3976N
